Which one of the following is the unit of specific weight?
Explanation: Specific weight(γ) is defined as the weight(w) per unit volume(V ), i.e.,
γ = w / v
Thus, unit of is N / m^{3}.
The specific gravity of a liquid has
Explanation: The specific gravity of a liquid is the ratio of two similar quantities (densities) which makes it unitless.
The specific volume of a liquid is the reciprocal of
Explanation: Specific volume(v) is defined as the volume(V ) per unit mass(m).
v = v⁄m = 1 / m⁄v = 1⁄p
where p is the mass density.
Match the following physical quantities in Group 1 with their dimensions in Group 2.
1. Mass Density (p) A. [M^{0} L^{ 0 }T ^{0 }]
2. Specific Gravity B. [M L^{– 1 }T^{ – 1 }]
3. Specific Volume (v) C. [M^{1 }L^{ 3 }T ^{0}^{ }]
4. Specific Weight (γ) D. [M^{1} L^{3} T ^{0 }]
5. Dynamic viscosity (μ) E. [M L^{– 2 }T ^{– 2 }]
Explanation:
Mass Density(p) is defined as the mass(m) per unit volume(V ), i.e.,
[p] = [m]/[v] = [m] /[L^{3}] = [ML^{3}]
The specific gravity of a liquid is the ratio of two similar quantities (densities) which makes it dimensionless.
Specific volume(v) is defined as the volume(V ) per unit mass(m). Thus,
[v] = [V]/[m] = [L^{3}]/[M] = [M^{1}L^{3}].
Specific weight(γ) is defined as the weight(w) per unit volume(V ), i.e.,
Which of the following forces generally act on fluid while considering fluid dynamics?
1. Viscous force
2. Pressure force
3. Gravity force
4. Turbulent force
5. Compressibility force
Which property of the fluid offers resistance to deformation under the action of shear force?
The study of force which produces motion in a fluid is called as
Explanation: Fluid dynamics is the study of forces responsible for the motion of fluids.
The specific weight of the fluid depends upon
Two fluids 1 and 2 have mass densities of p1 and p2 respectively. If p1 > p2, which one of the following expressions will represent the relation between their specific volumes v1 and v2?
Explanation: Specific volume(v) is defined as the volume(V ) per unit mass(m).
v = v⁄m = 1 / m⁄v = 1⁄p
where p is the mass density. Thus, if p1 > p2, the relation between the specific volumes v1 and v2
will be represented by v1 < v2.
A beaker is filled with a liquid up to the mark of one litre and weighed. The weight of the liquid is found to be 6.5 N. The specific weight of the liquid will be
Explanation: Specific weight(γ) is defined as the weight(w) per unit volume(V ), i.e.,
γ = w⁄V
Thus, γ = 6.5 ⁄10^{3} N ⁄ m^{3} = 6.5 kN/m^{3}.
Use Code STAYHOME200 and get INR 200 additional OFF

Use Coupon Code 




