Choose the function f(t); –∞ < t < ∞, for which a Fourier series cannot be defined.
The trigonometric Fourier series for the waveform f(t) shown below contains
From figure it’s an even function. so only cosine terms are present in the series and for DC value,
So DC take negative value.
Which of the following functions would have only odd powers of x in its Taylor series expansion about the point x = 0?
The Taylor series expansion of
The sum of the infinite series,
The summation of series
Fourier series for the waveform, f (t) shown in fig. is
From the figure, we say f (x) is even functions. so choice (c) is correct.
The Fourier Series coefficients, of a periodic signal x (t), expressed as
are given by
For the function of a complex variable W = ln Z (where, W = u + jv and Z = x + jy), the u = constant lines get mapped in Z-plane as
ii, where i = √−1, is given by
Assuming and t is a real number
The modulus of the complex number
Using Cauchy’s integral theorem, the value of the integral (integration being taken in counter clockwise direction)
Here f (z) has a singularities at z i / 3
Which one of the following is NOT true for complex number Z1and Z2 ?
(a) is true since
(b) is true by triangle inequality of complex number.
(c) is not true since |Z1 − Z2 |≥|Z1 |– |Z2 |
(d) is true since
For the equation, s3 - 4s2 + s + 6 =0
The number of roots in the left half of s-plane will be
Number of sign changes in the first column is two, therefore the number of roots in the left half splane is 2
The value of the integral of the complex function
Along the path |s| = 3 is
f (s) has singularities at s =−1, −2 which are inside the given circle
For the function of a complex variable z, the point z = 0 is
Therefore the function has z = 0 is a pole of order 2.
The polynomial p(x) = x5 + x + 2 has
As, P(x) of degree 5 .So other four roots are complex.
If z = x + jy, where x and y are real, the value of |ejz| is
The root mean squared value of x(t) = 3 + 2 sin (t) cos (2t) is
x(t) = 3 + 2 sin t cos 2t
x(t) = 3 + sin 3t – sin t
∴ Root mean square value
We wish to solve x2 – 2 = 0 by Netwon Raphson technique. Let the initial guess b x0 = 1.0 Subsequent estimate of x(i.e.x1) will be:
The order of error is the Simpson’s rule for numerical integration with a step size h is
The table below gives values of a function F(x) obtained for values of x at intervals of 0.25.
The value of the integral of the function between the limits 0 to 1 using Simpson’s rule is
A differential equation has to be solved using trapezoidal rule of integration with a step size h=0.01s. Function u(t) indicates a unit step function. If x(0-)=0, then value of x at t=0.01s will be given by
Consider the series obtained from the Newton-Raphson method. The series converges to
The series converges when X n+1= Xn =α
Given a>0, we wish to calculate its reciprocal value 1/a by using Newton-Raphson method :
for f(x) = 0. For a=7 and starting wkith x0 = 0.2. the first 2 iterations will be
With a 1 unit change in b, what is the change in x in the solution of the system of equations x + y = 2, 1.01 x + 0.99 y = b?
Given x + y = 2 …………….. (i)
1.01 x + 0.99 y = b …………….. (ii)
Multiply 0.99 is equation (i), and subtract from equation (ii), we get
The accuracy of Simpson's rule quadrature for a step size h is