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Figure shows the displacement – time graph of a particle moving along X – axis.
Because velocity is the slope of the x-t graph.(dx/dt=V) and by looking at the graph it can be seen that upto time T0 slope is constant so velocity will be constant and after time T0 slope is zero ( line is parallel to X axis) so the velocity will be zero.
The graph represents the velocity time for the first 4 seconds of motion. The distance covered is
Calculate the area of the graph as area of v-t grph gives dis. 1/2×4×15=30
A person goes from his home to his office taking one hour. There he works for 2 hours and then in half hour reaches home back. A representative displacement-time graph
We have given in the information that the person is in his office for two hours hence his position must not vary for two hours, that is the horizontal part in the graph which is only observed in the graph of option c.
Speed time graph of a particle moving along a fixed direction is shown in the figure below. The average speed of the particle over the interval: t = 0 s to 10 s.
From the given graph we get that the area of the given graph is total distance covered that is
= ½ x 10 x 12
And total time taken is 10 sec
Thus average speed is 60m / 10sec
= 6 m/s
The acceleration at any instant is the slope of the tangent of the ________ curve at that instant:
This can be verified graphically
ObtaIning instantaneous acceleration from graph
Slope of displacement time graph or x-t graph gives us the particles’ ____________.
Velocity is a physical vector quantity; both magnitude and direction are needed to define it. The scalar absolute value (magnitude) of velocity is called "speed", being a coherent derived unit whose quantity is measured in the SI (metric system) as metres per second (m/s) or as the SI base unit of (m⋅s−1).
Two balls of equal mass and of Perfectly elastic material are lying on the floor. One of the balls with velocity V is made to strike the second ball. Both the balls after impact will move with a velocity
Let two balls A and B have mass mA, mB respectively, and their initial velocities are uA and uB. After the collision, they will move with the same velocity, vo.
Given that mass of both balls are same.
So mA = mB = m
uA = V, uB = 0
From the Concept of Momentum Conservation:
mAuA + mBuB = (m+m)vo
mV = 2mvo
vo = V/2
Both the balls after impact will move with velocity v/2.
On velocity-time graph when two curves coincide, the objects will have
A velocity time graph represents the velocity of an object at a very certain time. If two curves collide that means that their velocities at the given time are equal. Their acceleration may or may not be equal depending upon the slope of the curve at the point of intersection.
Which position – time graph represents the motion of two objects that will never meet?
In the given all options we can see that curves in graph A and D meet in the first quadrant while the curve in option b meets in the second quadrant but those of option c are parallel and hence they never meet.
Linear inequalities are graphically represented on Cartesian plane by a
The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality. The boundary line is dashed for > and < and solid for ≤ and ≥.
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