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Test: Heredity And Variation 7 - From Past 28 Years Questions - NEET MCQ


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25 Questions MCQ Test - Test: Heredity And Variation 7 - From Past 28 Years Questions

Test: Heredity And Variation 7 - From Past 28 Years Questions for NEET 2024 is part of NEET preparation. The Test: Heredity And Variation 7 - From Past 28 Years Questions questions and answers have been prepared according to the NEET exam syllabus.The Test: Heredity And Variation 7 - From Past 28 Years Questions MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Heredity And Variation 7 - From Past 28 Years Questions below.
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Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 1

Multiple alleles control inheritance of

[1991]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 1

Multiple alleles control inheritance of blood groups in human. A, B, O blood group system is found in humans where the allele IA for A antigen is codominant with the allele IB for the B antigen. Both IA and IB are completely dominant to the allele P Hierarchy of dominance relationships is symbolised as(IA = IB) > IO.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 2

A man of A-blood group marries a women of AB blood group. Which type of progeny would indicate that man is heterozygous A?

[1991]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 2

IAIO × IAIB gives us the following genotypes IAIA, IOIB, IAIB.

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Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 3

A colour blind girl is rare because she will be born only when

[1991]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 3

The genotype of the mother was to be either XC XC or XCX and that of father XCY so that the daughter becomes colour blind.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 4

An organism with two identical alleles is

[1992]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 4

Homozygous individuals have identical mendelian factors or genes for a character (TT or tt). They are always pure for a particular trait (character).

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 5

Segregation of Mendelian factors (no linkage, no crossing over) occurs during

[1992]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 5

At anaphase I, actual segregation occurs, but two similar alleles occur in the dyad chromosome which separate at anaphase II.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 6

In a cross between AABB × aabb, the ratio of F2 genotypes between AABB, AaBB, Aabb and aabb would be

[1992]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 6

Genotype is the genetic make up of an individual irrespective of the mendelian characters or genes impressing.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 7

A gene pair hides the effect of another. The phenomenon is

[1992, 95, 99]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 7

Epsitasis is the phenomenon of masking or supressing the phenotypic impression of a gene pair by a non allelic gene pair which impresses its own effect.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 8

An allele is dominant if it is expressed in

[1992]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 8

Dominant alleles expresses itself in the homozygous as well as heterozygous condition. It is denoted by capital letter.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 9

A child of O-group has B-group father. The genotype of father will be

[1992]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 9

The genotype of the child would be IºIº (recessive). Hence the genotype of the father can only be IBIO.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 10

In human beings 45 chromosomes/single X/ XO abnormality causes

[1992]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 10

Turner syndrome encompassess several chromosomal abnormalities, of which monosomy X is the most common. It occurs in 1 out of every 2500 female births. Instead of the normal XX sex chromosomes for a female, only one X chromosome is present and fully functional. This is called 45,X or 45,X0, although other genetic variants occur. In Turner syndrome, female sexual characteristics are present but generally underdeveloped.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 11

Down's syndrome is due to

[1992]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 11

Down's syndrome is due to non-disjunction of chromosomes. Non-disjunction means absence of sepration of two homologous X chromosomes during anaphase-I of meiosis. Both X-chromosomes go together to same pole. Other pole will receive no X-chromosome.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 12

A colour blind mother and normal father would have

[1992, 94]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 12

When a colour blind woman marries a normal man the recessive homozygous gene is expressed in sons whereas the daughters become carriers.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 13

Out of 8 ascospores formed in Neurospora the arrangement is 2a : 4a : 2a showing

[1992]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 13

In Neurospora , products of meiosis remain linearly arranged and undergo one mitosis. Crossing over occurs in four strand stage.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 14

When a certain character is inherited only through female parent, it probably represents

[1992]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 14

Plasma genes present in the maternal cytoplasm are transmitted to offspring hence this type of inheritance is termed as cytoplasmic or maternal inheritance.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 15

Mendel studied inheritance of seven pairs of traits in Pea which can have 21 possible combinations. If you are told that in one of these combinations, independent assortment is not observed in later studies, your reaction will be

[1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 15

Law of independent assortment is applicable to only those factors or genes which are located on different chromosomes. Probably the characters were present on same chromosome and showed linkage which Mendel might not have studied.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 16

A polygenic inheritance in human beings is

[1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 16

Polygenic inheritance show cumulative effect i.e. two independent dominant genes produce additive effect on an individual.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 17

Nucleosome core is made of

[1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 17

The four histone proteins constituting the core of nucleosome are H2A, H2B, H3, H4.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 18

Sex is determined in human beings

[1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 18

Sex of human body is determined by the karyotype of the zygote or fertilized egg. Sex of the baby depends upon the sperm which fertilizes the ovum.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 19

Which crop variety is not due to induced mutations ?

[1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 19

It was genetically modified to get high lipid contents.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 20

Haploids are preferred over diploids for mutation studies because in haploids [1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 20

The haploid organisms readily express the phenotypes of the new mutations because there is no hindrance of dominance.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 21

Two dominant nonallelic genes are 50 map units apart. The linkage is

[1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 21

Chromosome mapping is based on the fact that genes are linearly arranged on the chromosome and frequency of crossing over is directly proportional to the distance between two genes. Dominant genes show cis arrangement. At 50 map units cis is changed to trans & vice-versa hence no fixed linkage is present.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 22

Of a normal couple, half the sons are haemophilic while half the daughters are carriers. The gene is located on

[1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 22

Since half the sons are haemophilic so the genes for haemophilia is located on X-chromosome of mother.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 23

Which of the following issuitable for experiment on linkage

[1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 23

Due to linkage the genes present on same chromosome stay together during transmission. All other combinations except AABB × aabb show recombination which do not show linkage and hence not suitable for experiments on linkage.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 24

Mr. Kapoor has Bb autosomal gene pair and d allele sex-linked. What shall be proportion of Bd in sperms

[1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 24

Genotype of Mr. Kapoor will be Bb d-hence one fourth of the sperms will have Bd.

Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 25

Of both normal parents, the chance of a male child becoming colour blind are

[1993]

Detailed Solution for Test: Heredity And Variation 7 - From Past 28 Years Questions - Question 25

On crossing carrier colour-blind woman with a normal man, the sons become colour blind. This is an example of criss cross inheritance. The genes for colourblindness is coming from mother's father.

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