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Find the length of each side of an equilateral triangle having area of 9 root 3 cm square
Given area of equilateral triangle = 9√3 cm²
Also,
Area of the equilateral triangle = √3/4 × (side)²
So,
√3/4 × (side)² = 9√3
side² = (9√3 × 4)/√3
side² = 36
side = √36
side = 6cm
If the height of a parallelogram having 500 cm^{2} as the area is 20 cm, then its base is of length
A = bh
500 = b x 20
b = 500/20
b = 25 cm
The area of an isosceles right angled triangle of equal side 30 cm, is given as
If side of a scalene △ is doubled then area would be increased by
An isosceles right triangle has area 8 cm^{2}. The length of its hypotenuse is :
If the area of an equilateral triangle is 36√3 cm^{2}, then the perimeter of the triangle is
Given the product of diagonals of a rhombus ABCD is 2500 cm^{2}, its area is
The area and length of one diagonal of a rhombus are given as 200 cm^{2} and 10 cm respectively. The length of other diagonal is
In each side of a △ is halved then its perimeter will be decreased by
The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 70 paise per cm^{2} is
The area of a right angled triangle if the radius of its circumcircle is 3 cm and altitude drawn to the hypotenuse is 2 cm.
The area of one triangular part of a rhombus ABCD is given as 125 cm^{2}. The area of rhombus ABCD is
Length of perpendicular drawn on smallest side of scalene triangle is
The sides of a triangle are in ratio 3 : 4 : 5. If the perimeter of the triangle is 84 cm, then area of the triangle is :
The perimeter of a rhombus is 20 cm. If one of its diagonals is 6 cm, then its area is
Area of an isosceles triangle ABC with AB = a = AC and BC = b is
Each side of an equilateral triangle measures 10 cm. Then the area of the triangle is
Length of perpendicular drawn on longest side of a scale △ is
Each side of an equilateral triangle is 2x cm. If x√3 = √48, then area of the triangle is :
The area of a rhombus of 96 cm^{2}. If one of its diagonals is 16 cm, then the length of its side is
The area of quadrilateral ABCD whose diagonals are perpendicular and of lengths 12 cm, 8 cm is
The area of a parallelogram whose base is 32 m and the corresponding altitude is 6 m is
area of parallelogram = base x height
=32 x 6 = 192 m^{2}
Semiperimeter of scalene triangle of side k, 2k and 3k is
The sides of a triangle are x, y and z. If x + y = 7 m, y + z = 9 m, and z + x = 8 m, then area of the triangle is :
x + y = 7....(1)
y + z = 9....(2)
z + x = 8....(3)
So, 2(x+y+z) = 24
x+y+z = 12
Now, y + z = 9 then x = 3
z + x = 8 then y = 4
x + y = 7 then z = 5
We can see that, this becomes a right angled triangle.
Hence, Area of triangle = 1/2 * base * perpendicular
= 1/2 * 4 * 3
= 6 sq unit.
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