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Test: Inductance & AC Generator (January 29) - NEET MCQ


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10 Questions MCQ Test Daily Test for NEET Preparation - Test: Inductance & AC Generator (January 29)

Test: Inductance & AC Generator (January 29) for NEET 2024 is part of Daily Test for NEET Preparation preparation. The Test: Inductance & AC Generator (January 29) questions and answers have been prepared according to the NEET exam syllabus.The Test: Inductance & AC Generator (January 29) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Inductance & AC Generator (January 29) below.
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Test: Inductance & AC Generator (January 29) - Question 1

Efficiency of electric motor is always less than

Detailed Solution for Test: Inductance & AC Generator (January 29) - Question 1

Electric motors have an efficiency of less than 100% because there is ALWAYS energy loss through any mechanism imaginable.

Test: Inductance & AC Generator (January 29) - Question 2

Induced e.m.f is given by it will be maximum when ,

Detailed Solution for Test: Inductance & AC Generator (January 29) - Question 2

The rate of change of flux linkage is directly proportional to the induced EMF in a coil. Hence, the EMF is maximum when the rate of change of flux linkage is maximum.

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Test: Inductance & AC Generator (January 29) - Question 3

If a capacitor of capacitance 9.2F has a voltage of 22.5V across it. Calculate the energy of the capacitor.

Detailed Solution for Test: Inductance & AC Generator (January 29) - Question 3

E = CV2/2

= 9.2 x (22.5)2/2

= 2328.75 J

Test: Inductance & AC Generator (January 29) - Question 4

A solenoid coil has 10 turns per cm along its length and a cross sectional area of 10 cm2. 100 turns of another wire are wound round the first solenoid coaxially. The two coils are electrically insulated from each other. The mutual inductance between the two coils is​

Detailed Solution for Test: Inductance & AC Generator (January 29) - Question 4

n1=10 turns per cm, =1000 turns per metre
n2l=100, A=10 c=0.1 m2, M=μ0n1(n2l) A
=4πx10-7×1000×100×0.1H=0.13mh

Test: Inductance & AC Generator (January 29) - Question 5

Solve : 4 cos q _ 3 sec q = 2 tan q

 


Test: Inductance & AC Generator (January 29) - Question 6

Two pure inductors are connected in series, if their self inductance is L. Find the total inductance

Detailed Solution for Test: Inductance & AC Generator (January 29) - Question 6

The total inductance of inductors connected in series is given by the following formula:
Leq = L1 + L2
Substituting the values in the equation, we get the total inductance as
Leq = L + L = 2L
Hence, the total inductance of two inductors connected in series is 2L.

Test: Inductance & AC Generator (January 29) - Question 7

Which of the following is used to determine the direction of induced current in a generator?

Detailed Solution for Test: Inductance & AC Generator (January 29) - Question 7

Fleming's Right hand rule: Hold a current-carrying conductor in your right hand with thumb in the direction of the current, the direction of the field lines will be the direction of your fingers.

Test: Inductance & AC Generator (January 29) - Question 8

The unit of self inductance of a coil is

Detailed Solution for Test: Inductance & AC Generator (January 29) - Question 8

Now, e=L(di/dt)
L=e/(di/dt)
1 henry=1 volt/(1 ampere/second)

Test: Inductance & AC Generator (January 29) - Question 9

The mutual induction does not depend on which of the following factors

Detailed Solution for Test: Inductance & AC Generator (January 29) - Question 9

Mutual inductance is the phenomena where an adjoining wire coil induces the voltage from the magnetic field produced by a wire coil. A transformer is a tool which is made up of two or more coils in close proximity to each other to create a situation of mutual inductance between the coils.The factors determining the value of mutual inductance are —
a. The number of turns of the coils
b. The geometric shape and size of the coils
c. The separation of the coils and
d. The angular orientation between the coils
So clearly it does not depend upon the current flow through both of the cells.

Test: Inductance & AC Generator (January 29) - Question 10

The factor, on which the frequency of an AC generator depends,

Detailed Solution for Test: Inductance & AC Generator (January 29) - Question 10

The answer provided in the forum is wrong, the correct answer would be option B and D both.
Solution:
Frequency of a.c, ν=w/2π​, where  w is the speed of rotation
Also, frequency is defined as the number of rotations that a coil rotates in one second.
 

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