Test: Inductances


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10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) | Test: Inductances

Test: Inductances for Electrical Engineering (EE) 2022 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Inductances questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Inductances MCQs are made for Electrical Engineering (EE) 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Inductances below.
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Test: Inductances - Question 1

Calculate the emf of a coil with turns 100 and flux rate 5 units.

Detailed Solution for Test: Inductances - Question 1

Answer: d
Explanation: The emf is the product of the turns of the coil and the flux rate. Thus e = -N dφ/dt, where the negative sign indicates that the emf induced is opposing the flux. Thus e = -100 x 5 = -500 units.

Test: Inductances - Question 2

The equivalent inductances of two coils 2H and 5H in series aiding flux with mutual inductance of 3H is

Detailed Solution for Test: Inductances - Question 2

Answer: d
Explanation: The equivalent inductance of two coils in series is given by L = L1 + L2 + 2M, where L1 and L2 are the self inductances and M is the mutual inductance. Thus L = 2 + 5 + 2(3) = 13H.

Test: Inductances - Question 3

The expression for the inductance in terms of turns, flux and current is given by

Detailed Solution for Test: Inductances - Question 3

Answer: a
Explanation: We know that e = -N dφ/dt and also e = -L di/dt. On equating both we get, L = Ndφ/di is the expression for inductance.

Test: Inductances - Question 4

The equivalent inductance of two coils with series opposing flux having inductances 7H and 2H with a mutual inductance of 1H.

Detailed Solution for Test: Inductances - Question 4

Answer: b
Explanation: The equivalent inductance of two coils in series with opposing flux is L = L1 + L2 – 2M, where L1 and L2 are the self inductances and M is the mutual inductance. Thus L = 7 + 2 – 2(1) = 7H.

Test: Inductances - Question 5

A coil is said to be loosely coupled with which of the following conditions?

Detailed Solution for Test: Inductances - Question 5

Answer: d
Explanation: k is the coefficient of coupling. It lies between 0 and 1. For loosely coupled coil, the coefficient of coupling will be very less. Thus the condition K<0.5 is true.

Test: Inductances - Question 6

With unity coupling, the mutual inductance will be

Detailed Solution for Test: Inductances - Question 6

Answer: c
Explanation: The expression for mutual inductance is given by M = k √(L1 x L2), where k is the coefficient of coupling. For unity coupling, k = 1, then M = √(L1 x L2).

Test: Inductances - Question 7

The inductance is proportional to the ratio of flux to current. State True/False. 

Detailed Solution for Test: Inductances - Question 7

Answer: a
Explanation: The expression is given by L = Ndφ/di. It can be seen that L is proportional to the ratio of flux to current. Thus the statement is true.

Test: Inductances - Question 8

Calculate the mutual inductance of two tightly coupled coils with inductances 49H and 9H.

Detailed Solution for Test: Inductances - Question 8

Answer: a
Explanation: For tightly coupled coils, the coefficient of coupling is unity. Then the mutual inductance will be M = √(L1 x L2)= √(49 x 9) = 21 units.

Test: Inductances - Question 9

Find the inductance of a coil with turns 50, flux 3 units and a current of 0.5A

Detailed Solution for Test: Inductances - Question 9

Answer: b
Explanation: The self inductance of a coil is given by L = Nφ/I, where N = 50, φ = 3 and I = 0.5. Thus L = 50 x 3/0.5 = 300 units.

Test: Inductances - Question 10

The inductance of a coaxial cable with inner radius a and outer radius b, from a distance d, is given by

Detailed Solution for Test: Inductances - Question 10

Answer: a
Explanation: The inductance of a coaxial cable with inner radius a and outer radius b, from a distance d, is a standard formula derived from the definition of the inductance. This is given by L = μd ln(b/a)/2π.

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