Which integer is greater than –5?
An integer on the horizontal number line is greater than the number on its left and less than the number on its right. Therefore, the smallest negative integer is the biggest one.
So -1 will be greater than -5. Thus, option B is the correct answer.
If a x (b − c) is 8 for a = 2, b = 10 and c = 6 then a x b − a x c is equal to:
a x (b − c) = a x b - a x c
= (a x b) - (a x c)
= (2 x 10) - (2 x 6)
= 20 - 12
So, option D is the correct answer.
The product of three negative integers is:
If the number of negative integers in a product is odd, then the product is a negative integer.
The additive identity for integers is:
According to Distributive Law of Multiplication over Addition, a x (b + c) must be equal to:
According to Distributive Law of Multiplication over Addition:
a x (b + c) = a x b + a x c
Which amongst the following is the largest?
I-89I, -89, -21, I-21I
The multiplicative identity for integers is:
What will be the additive inverse of 7?
How many integers are there between -8 and 2 (excluding -8 and 2)?
The value of [(-4) x (-9) x (-25)] ÷ [(-2) x (-3) x (-5)] is: