The value of is given by
The principal value of tan-1 (-1) is given by:
Let y = tan-1(-1)
tan y = -1
tan y = tan(-π/4)
Range of principal value of tan-1 is
(-π/2 , π/2)
SInce - 1 is negative,
the principle value of tan-1(-1) is - π/4
if 5 sin θ = 3, then is equal to
sin θ is 3/5.
(secθ + tanθ)/(secθ - tanθ)
We get, (1+sin θ)/(1-sin θ)
Since sin-1(-π/2) = -sin-1(π/2) = -1
so, cot -1(-1)
let (- cot-11) = α
cot α = -1 = cot (π/2+π/4) = 3π/4
What is the solution of cot(sin-1x)?
Let sin-1x = y.
From ∆ABC, we get
y = sin-1x
Find the value of sin-1(3/5) + sin-1(4/5) + cos-1(√3/2).
Using the formula sin-1x + sin-1y
Find the value of sin-1(513) + cos-1(35).
Find the value of tan-1(1/3) + tan-1(1/5) + tan-1(1/7).
What is the value of 2 tan-1x?
Let 2 tan-1x = y