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Find the value of v if v_{1 }= 20V and value of current source is 6A
The current through the 10 ohm resistor = v_{1 }/ 10 = 2A
Applying KCL at node 1: i_{5 }= i_{10 }+ i_{2}
i_{2 }= 6  2 = 4A
Thus the drop in the 2 ohm resistor = 4×2 = 8V
v_{1 }= 20V; hence v_{2 }= 20v across 2 ohm resistor = 20  8 = 12V
v_{2 }= v since they are connected in parallel.
v = 12V
KCL states that the total current leaving the junction is equal to the current entering it. In this case, the current entering the junction is 5 A + 10 A = 15A
Calculate the current across the 20 ohm resistor.
Assume lower terminal of 20 ohm at 0V and upper terminal at V volt and applying KCL, we get V/10 + V/20 = 1
V = (20 / 3) V
So, current through 20 ohm = V/20 = (20/3) / 20 = 1/3 = 0.33V
Calculate the value of I_{3}, if I_{1 }= 2A and I_{2 }= 3A
According to KCL, I_{1 }+ I_{2 }+ I_{3 }= 0
Hence I_{3 }=  (I_{1 }+ I_{2}) =  5A
Find the value of i_{2}, i_{4 }and i_{5 }if i_{1 }= 3A, i_{3 }= 1A and i_{6 }= 1A
What is the value of current if a 50C charge flows in a conductor over a period of 5 seconds?
Current = Charge/Time
Here charge = 50C and time = 5 seconds
so current = 50/5 = 10A
KCL states that the amount of charge entering a junction is equal to the amount of charge leaving it, hence it is the conservation of charge.
KCL states that the amount of charge leaving a node is equal to the amount of charge entering it, hence it is applied at nodes.
KCL is applied for different nodes of a network whether it is planar or nonplanar.
At the junction, I  2 + 3  4  5 = 0
Hence I = 8A
Using KVL, 12  V1  8 = 0.
V1 = 4V
8  V2  2 = 0
V2 = 6V
KCL states that the amount of charge entering a junction is equal to the amount of charge leaving it, hence it is the conservation of charge.
Calculate the voltage across the 10 ohm resistor.
Using voltage divider rule, V = 10*12/30 = 4V
Find the value of the currents I1 and I2.
Using KVL, the matrix to find the loop currents are:
MATRIX 10 100 * i1 + 100 * i2 = 0
MATRIX 10  200 * i2 + 100 * i1 = 0
I1 = 0.3, I2 = 0.2
The sum of the voltages over any closed loop is equal to __________
According to KVL, the sum of the voltage over any closed loop is equal to 0.
What is the basic law that has to be followed in order to analyze any circuit?
Kirchhoff’s laws, namely Kirchhoff’s Current Law and Kirchhoff’s Voltage law are the basic laws in order to analyze a circuit.
Every____________ is a ____________ but every __________ is not a __________
According to Kirchhoff’s Voltage Law, Every mesh is a loop but every loop is not a mesh.
V_{eq} = 10 + 5 20 = 5u
R_{eq} = 5 + 2 + 3 = 10Ω
I = V/R = 5/10 = 0.5A.
For branch A: V_{AC}= 15 * 20 / (25+15) = 7.5V
For branch B: V_{BC}= 10 * 20 / (10+40) = 4V
Applying KVL to loop ABC
V_{AB}+V_{BC}+V_{CA }= 0
V_{AB }= 3.5V
Mesh analysis helps us to utilize the different voltages in the circuit as well as the I_{R }products in the circuit which is nothing but KVL.
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