Test: Kirchhoff’s Current & Voltage Law

# Test: Kirchhoff’s Current & Voltage Law

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## 20 Questions MCQ Test Basic Electrical Technology | Test: Kirchhoff’s Current & Voltage Law

Test: Kirchhoff’s Current & Voltage Law for Electrical Engineering (EE) 2023 is part of Basic Electrical Technology preparation. The Test: Kirchhoff’s Current & Voltage Law questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Kirchhoff’s Current & Voltage Law MCQs are made for Electrical Engineering (EE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Kirchhoff’s Current & Voltage Law below.
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Test: Kirchhoff’s Current & Voltage Law - Question 1

### Find the value of v if v1 = 20V and value of current source is 6A Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 1

The current through the 10 ohm resistor = v1 / 10 = 2A

Applying KCL at node 1: i5 = i10 + i2

i= 6 - 2 = 4A

Thus the drop in the 2 ohm resistor = 4×2 = 8V

v1 = 20V; hence v2 = 20-v across 2 ohm resistor = 20 - 8 = 12V
v2 = v since they are connected in parallel.
v = 12V

Test: Kirchhoff’s Current & Voltage Law - Question 2

### Calculate the current A. Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 2

KCL states that the total current leaving the junction is equal to the current entering it. In this case, the current entering the junction is 5 A + 10 A = 15A

Test: Kirchhoff’s Current & Voltage Law - Question 3

### Calculate the current across the 20 ohm resistor. Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 3

Assume lower terminal of 20 ohm at 0V and upper terminal at V volt and applying KCL, we get V/10 + V/20 = 1

V = (20 / 3) V

So, current through 20 ohm = V/20 = (20/3) / 20 = 1/3 = 0.33V

Test: Kirchhoff’s Current & Voltage Law - Question 4

Calculate the value of I3, if I= 2A and I= 3A Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 4

According to KCL, I+ I+ I= 0

Hence I= - (I+ I2) = - 5A

Test: Kirchhoff’s Current & Voltage Law - Question 5

Find the value of i2, i4 and i5 if i= 3A, i= 1A and i= 1A Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 5
•  At junction a: i- i3 - i2 = 0
i= 2A
• At junction b: i+ i- i= 0
i= -1A
• At junction c: i- i+ i= 0
i= 2A
Test: Kirchhoff’s Current & Voltage Law - Question 6

What is the value of current if a 50C charge flows in a conductor over a period of 5 seconds?

Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 6

Current = Charge/Time

Here charge = 50C and time = 5 seconds

so current = 50/5 = 10A

Test: Kirchhoff’s Current & Voltage Law - Question 7

KCL deals with the conservation of?

Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 7

KCL states that the amount of charge entering a junction is equal to the amount of charge leaving it, hence it is the conservation of charge.

Test: Kirchhoff’s Current & Voltage Law - Question 8

KCL is applied at _________

Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 8

KCL states that the amount of charge leaving a node is equal to the amount of charge entering it, hence it is applied at nodes.

Test: Kirchhoff’s Current & Voltage Law - Question 9

KCL can be applied for __________

Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 9

KCL is applied for different nodes of a network whether it is planar or non-planar.

Test: Kirchhoff’s Current & Voltage Law - Question 10

What is the value of the current I? Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 10

At the junction, I - 2 + 3 - 4 - 5 = 0

Hence I = 8A

Test: Kirchhoff’s Current & Voltage Law - Question 11

Calculate the value of V1 and V2. Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 11

Using KVL, 12 - V1 - 8 = 0.

V1 = 4V

8 - V2 - 2 = 0

V2 = 6V

Test: Kirchhoff’s Current & Voltage Law - Question 12

KCL deals with the conservation of?

Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 12

KCL states that the amount of charge entering a junction is equal to the amount of charge leaving it, hence it is the conservation of charge.

Test: Kirchhoff’s Current & Voltage Law - Question 13

Calculate the voltage across the 10 ohm resistor. Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 13

Using voltage divider rule, V = 10*12/30 = 4V

Test: Kirchhoff’s Current & Voltage Law - Question 14

Find the value of the currents I1 and I2. Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 14

Using KVL, the matrix to find the loop currents are:
MATRIX 10 -100 * i1 + 100 * i2 = 0
MATRIX  10 - 200 * i2 + 100 * i1 = 0
I1 = 0.3, I2 = 0.2

Test: Kirchhoff’s Current & Voltage Law - Question 15

The sum of the voltages over any closed loop is equal to __________

Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 15

According to KVL, the sum of the voltage over any closed loop is equal to 0.

Test: Kirchhoff’s Current & Voltage Law - Question 16

What is the basic law that has to be followed in order to analyze any circuit?

Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 16

Kirchhoff’s laws, namely Kirchhoff’s Current Law and Kirchhoff’s Voltage law are the basic laws in order to analyze a circuit.

Test: Kirchhoff’s Current & Voltage Law - Question 17

Every____________ is a ____________ but every __________ is not a __________

Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 17

According to Kirchhoff’s Voltage Law, Every mesh is a loop but every loop is not a mesh.

Test: Kirchhoff’s Current & Voltage Law - Question 18

Solve for I. Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 18

Veq = 10 + 5 -20 = -5u
Req = 5 + 2 + 3 = 10Ω
I = V/R = -5/10 = -0.5A.

Test: Kirchhoff’s Current & Voltage Law - Question 19

Calculate VAB. Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 19

For branch A: VAC= 15 * 20 / (25+15) = 7.5V
For branch B: VBC= 10 * 20 / (10+40) = 4V
Applying KVL to loop ABC
VAB+VBC+VCA = 0
VAB = 3.5V

Test: Kirchhoff’s Current & Voltage Law - Question 20

KVL is applied in ____________

Detailed Solution for Test: Kirchhoff’s Current & Voltage Law - Question 20

Mesh analysis helps us to utilize the different voltages in the circuit as well as the IR products in the circuit which is nothing but KVL.

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