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If f(x) is an odd function then
If f(x) and g(x) are two functions of x such that f(x) + g(x) = e^{x} and f(x) – g(x) = e ^{–x} then
Let f(x) = x when x >0
= 0 when x = 0
= – x when x < 0
Now f(x) is
If f(x) = 5+3x for x > 0 and f(x) = 5 – 3x for x < 0 then f(x) is
Then the given function is not continuous for
A function f(x) is defined by f(x) = (x–2)+1 over all real values of x, now f(x) is
A function f(x) defined as follows f(x) = x+1 when x = 3 – px when x > 1
The value of p for which f(x) is continuous at x = 1 is
A function f(x) is defined as follows :
f(x)= x when x < 1
= 1+x when x > 1
= 3/2 when x = 1
Then f(x) is
Let f(x) = x/x. Now f(x) is
f(x) = x–1 when x > 0
= – ½ when x = 0
= x + 1 when x < 0
f(x) is
f(x) = (x^{2} – 1) / (x^{3} – 1) is undefined at x = 1 the value of f(x) at x = 1 such that it is continuous at x = 1 is
If f(x) = 3, when x <2
f(x) = kx2, when x is continuous at x = 2, then the value of k is
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