Test: Linear Inequalities In One Variable And Two Variables

 If x >0 then x will be positive and y less than 0 means it gets negative value
that means it lies in 4th quadrant. 

Numbers obtained in three throws are 5,3 and 6
Let the number obtained in fourth throw be x
Now, Sum > 20
5 + 3 + 6 + x > 20
14 + x > 20
x > 6(never wins)

x > 1 means x is greater than 1 in this equation the values of x can be 2,3,4,5.............∞
x < -1 means is less than -1 therefore values of x can be -2, -3, -4, -5............ -∞
So no common point for x
Hence there will be no solution

3(2 - x) ≥ 2(1 - x)
6 - 3x ≥ 2 - 2x
4 ≥ x

x > 1 and x > -1
Take two points 1,-1 on number line
Therefore x > 1

IQ = (MA*100)/CA
and 80 ≤ IQ ≤ 140
80 ≤ (MA*100)/CA ≤ 140
80 ≤ (MA*100)/12 ≤ 140
960 ≤ (MA*100) ≤ 1680
9.6 ≤ MA ≤ 16.8

x>2, the value of x is greater than 2. the value goes till infinity.
if X is equal or greater than 2 then we use solid dot, but it is only greater than 2
so the option c is correct.

Numbers obtained in three throws are 3, 5 and 6.
Let the number obtained in fourth throw be x.
Now, Sum > 20
=> 5 + 3 + 6 + x > 20
=> 14 + x > 20
=> x > 20 – 14
=> x > 6 (no one wins)