If log 2 = .301, find the number of digits in (125)25.
logy = 25 log 125
= 25 [log 1000 - 3 log 2]
= 25 x (2.097)
= 52 +
Hence 53 digits.
(75/35) x (49/25) x (jc/105) x (25/13) = 1 ⇒ x = 13
Which one of the following is true
x = (16/15) x (255/245) x (813/803) None of these is correct.
Find the value of the logarithmic expression in the questions below.
log (anbncn/anbncn) = log 1 = 0
log2 (9 - 2X) = 10log (3-x) Solve for x.
For x = 0, we have LHS
Log2 8 = 3.
RHS: 10log3 = 3.
We do not get LHS = RHS for either x = 3 or x = 6.
Thus, option (a) is correct.
Which one of the following is true
log (x - 13) + 3 log 2 = log (3x + 1)
log . 0867 = ?
Log 0.0867 = log (8.67/100) = log 8.67 - log 100 Log 8.67 - 2
log3x = 1/2
x = 31/2 = √3 .
If log10a = b, find the value of 103b in terms of a.
log10a = b ⇒ 10b = a ⇒ By definition of logs.
Thus 103b = (10b)3 = a3.
log (x2 - 6x + 6) = 0
Find x If logx = log 1.5 + log 12
log x = log 18 ⇒ x = 18
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