If log 2 = .301, find the number of digits in (125)^{25}.
logy = 25 log 125
= 25 [log 1000  3 log 2]
= 25 x (2.097)
= 52 +
Hence 53 digits.
(75/35) x (49/25) x (jc/105) x (25/13) = 1 ⇒ x = 13
Which one of the following is true
x = (16/15) x (25^{5}/24^{5}) x (81^{3}/80^{3}) None of these is correct.
Find the value of the logarithmic expression in the questions below.
log (a^{n}b^{n}c^{n}/a^{n}b^{n}c^{n}) = log 1 = 0
log_{2} (9  2^{X}) = 10^{log (3x)} Solve for x.
For x = 0, we have LHS
Log_{2} 8 = 3.
RHS: 10^{log3} = 3.
We do not get LHS = RHS for either x = 3 or x = 6.
Thus, option (a) is correct.
Which one of the following is true
log (x  13) + 3 log 2 = log (3x + 1)
log . 0867 = ?
Log 0.0867 = log (8.67/100) = log 8.67  log 100 Log 8.67  2
log_{3}x = 1/2
x = 3^{1/2} = √3 .
If log_{10}a = b, find the value of 10^{3b} in terms of a.
log_{10}a = b ⇒ 10^{b} = a ⇒ By definition of logs.
Thus 10^{3b} = (10^{b})^{3} = a^{3}.
log (x^{2}  6x + 6) = 0
Find x If logx = log 1.5 + log 12
log x = log 18 ⇒ x = 18
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