# Test: Magnetic Boundary Conditions

## 10 Questions MCQ Test Electromagnetic Fields Theory | Test: Magnetic Boundary Conditions

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Attempt Test: Magnetic Boundary Conditions | 10 questions in 10 minutes | Mock test for Electronics and Communication Engineering (ECE) preparation | Free important questions MCQ to study Electromagnetic Fields Theory for Electronics and Communication Engineering (ECE) Exam | Download free PDF with solutions
QUESTION: 1

### Find the correct relation between current density and magnetization.

Solution:

Explanation: The curl of the magnetization gives the magnetic field intensity theoretically. From Maxwell equation, we can correlate that with the current density (Ampere law)

QUESTION: 2

### The tangential component of the magnetic field intensity is continuous at the boundary of separation of two media. State True/False.

Solution:

Explanation: For two medium of separation, the tangential component of the magnetic field intensity will be continuous. This is analogous to the fact that the tangential component of the electric field intensity is continuous at the boundary.

QUESTION: 3

### In air, the tangential component of flux density is continuous at the boundary. State True/False.

Solution:

Explanation: Since the tangential component of the magnetic field intensity will be continuous and B = μH, in air, the tangential component of the flux density will also be continuous.

QUESTION: 4

The flux density of medium 1 has a normal component of 2.4 units, then the normal component of the flux density in the medium 2 will be

Solution:

Explanation: Unlike the electric fields, the magnetic flux density has normal component same in both the mediums. This gives Bn1 = Bn2.

QUESTION: 5

The normal component of magnetic field intensity at the boundary of separation of the medium will be

Solution:

Explanation: The normal component and tangential components of the magnetic flux density will be same. This holds good for any medium.

QUESTION: 6

The line integral of the magnetic field intensity is the

Solution:

Explanation: The line integral of the magnetic field intensity is given by ∫H.dl. This is same as the current component. From this relation, the Ampere law can be deduced.

QUESTION: 7

Find the magnetization of the material with susceptibility of 6 units and magnetic field intensity of 13 units.

Solution:

Explanation: The magnetization is the product of the susceptibility and the magnetic field intensity. Thus M = 6 x 13 = 78 units.

QUESTION: 8

Find the ratio of permeability of the two media when the wave is incident on the boundary at 45 degree and reflected by the boundary at 60 degree.

Solution:

Explanation: From the magnetic boundary conditions, the ratio of permeability μ1/μ2 = tan θ1/tan θ2 and θ1 = 45, θ2 = 60. Thus we get μ1/μ2 = 1/√3. The ratio will be 1:√3.

QUESTION: 9

Find the magnetic moment of a material with magnetization 5 units in a volume of 35 units.

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