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For the circuit given below i1 = 4 sin(2t) and i2 = 0
Q. v1 = ?
v1 = 2 d(i1)/dt + d(i2)/dt.
For the circuit given below i1 = 4 sin(2t) and i2 = 0
Q. v2 = ?
v2 = d(i1)/dt + d(i2)/dt.
If i1 = 0 and i2 = 2 sin(4t), the voltage v1 is
v1 = 3 d(i1)/dt – 3 d(i2)/dt.
If i1 = e^{(2t)} and i2 = 0, the voltage v1 is
v1 = 4 d(i1)/dt – 3 d(i2)/dt.
v1 = 2 d(i1)/dt – 2 d(i2)/dt.
v2 = 3 d(i1)/dt + 2 d(i2)/dt.
v1 = 2 d(i1)/dt – 2 d(i2)/dt.
v2 = 3 d(i1)/dt + 2 d(i2)/dt.
Leq = L1 + L2 – 2M.
Leq = L1 + L2 – 2M.
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