The contrapositive of (p∨q)→ r is
Contrapositive of p→q is ∼q→∼p.
∴ Contrapositive of (p∨q)⇒r is ∼r⇒∼(p∨q) i.e. ∼r⇒(∼p∧∼q).
The contrapositive of p→(∼q→∼r) is
Let p and q be two propositions. Then the inverse of the implication p→q is
Let p and q be two propositions. Then the contrapositive of the implication p→q is
Let p and q be two propositions. Then the implication ∼(p↔q)∼(p↔q) is :
p∧(q∧r) is logically equivalent to
Which of the following proposition is a tautology ?
The negation of the compound statement p∨(∼p∨q) is
The proposition p→∼(p∧∼q) is
The proposition (p→∼p)∧(∼p→p) is
Which of the following is equivalent to (p∧q) ?
Which of the following is logically equivalent to ∼(∼p→q) ?
∼(p⇒q)≡p∧∼q
∴ ∼(∼p⇒q) ≡∼p∧∼q
The contrapositive of the inverse of p⇒ ~q is
The inverse of p ⇒ ∼q is ∼p ⇒ q
The contrapositive of ∼p ⇒ q is ∼q ⇒ p. [∴ Contrapositive of p ⇒ q is∼q ⇒ p.]
p→q is logically equivalent to
The contrapositive of (∼p∧q)→ is
The negation of p∧∼(q∧r) is
The negation of q∨∼(p∧r) is
Which of the following is a contradiction?
Which of the following is logically equivalent to (p∧q) ?
The negation of the proposition q∨∼(p∧r) is
If p→(q∨r) is false , then the truth values of p , q and r, are respectively
The statement p ⇒ p∨q is
A tautology is a proposition is always true.
The statement p∨qp∨q is
Which of the following sentences is a statement ?
Let p and q be two prepositions given by p : I take only bread and butter in breakfast. q : I do not take anything in breakfast. Then , the compound proposition “ I take only bread and butter in breakfast or I do not take anything “ is represented by
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