Courses

# Test: Maxwell Law in Time Static Fields

## 10 Questions MCQ Test Electromagnetic Fields Theory | Test: Maxwell Law in Time Static Fields

Description
This mock test of Test: Maxwell Law in Time Static Fields for Electronics and Communication Engineering (ECE) helps you for every Electronics and Communication Engineering (ECE) entrance exam. This contains 10 Multiple Choice Questions for Electronics and Communication Engineering (ECE) Test: Maxwell Law in Time Static Fields (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Maxwell Law in Time Static Fields quiz give you a good mix of easy questions and tough questions. Electronics and Communication Engineering (ECE) students definitely take this Test: Maxwell Law in Time Static Fields exercise for a better result in the exam. You can find other Test: Maxwell Law in Time Static Fields extra questions, long questions & short questions for Electronics and Communication Engineering (ECE) on EduRev as well by searching above.
QUESTION: 1

### Calculate the emf in a material with flux linkage of 3.5t2 at 2 seconds.

Solution:

Explanation: The emf induced in a material with flux linkage is given by Vemf = -dλ/dt. On substituting λ= 3.5t2, we get emf = -7t. At time t = 2sec, the emf will be -14 units.

QUESTION: 2

### Find the emf induced in a coil of 60 turns with a flux rate of 3 units.

Solution:

Explanation: The emf induced is the product of the turns and the flux rate. Thus Vemf = -Ndφ/dt. On substituting N = 60 and dφ/dt = 3, we get emf as -60 x 3 = -180 units.

QUESTION: 3

### Find the electric field intensity of a charge 2.5C with a force of 3N.

Solution:

Explanation: The electric field intensity is the electric force per unit charge. It is given by E = F/q. On substituting F = 2.5 and q = 3, we get E = 3/2.5 units.

QUESTION: 4

The electric field intensity of a field with velocity 10m/s and flux density of 2.8 units is

Solution:

Explanation: The electric field is the product of the velocity and the magnetic flux density given by E = v x B. On substituting v = 10 and B = 2.8, we get E = 10 x 2.8 = 28 units.

QUESTION: 5

The line integral of the electric field intensity is

Solution:

Explanation: From the Maxwell first law, the transformer emf is given by the line integral of the electric field intensity. Thus the emf is given by ∫ E.dl.

QUESTION: 6

Which of the following relations is correct?

Solution:

Explanation: The emf induced in a material is given by the line integral of the electric field intensity. Thus EMF = ∫ E.dl is the correct relation.

QUESTION: 7

For static fields, the curl of E will be

Solution:

Explanation: For static fields, the charges will be constant and the field is constant. Thus curl of the electric field intensity will be zero. This implies the field is irrotational.

QUESTION: 8

The line integral of which parameter is zero for static fields?

Solution:

Explanation: The field is irrotational for static fields. Thus curl of E is zero. From Stokes theorem, the line integral of E is same as the surface integral of the curl of E. Since it is zero, the line integral of E will also be zero.

QUESTION: 9

The magnitude of the conduction current density for a magnetic field intensity of a vector yi + zj + xk will be

Solution:

Explanation: From the Ampere circuital law, the curl of H is the conduction current density. The curl of H = yi + zj + xk is –i – j – k. Thus conduction current density is –i – j – k. The magnitude will be √(1 + 1 + 1) = √3 = 1.732 units.

QUESTION: 10

The charge density of a field with a position vector as electric flux density is given by

Solution: