Test: Mechanical Properties of Materials - 2


10 Questions MCQ Test Solid Mechanics | Test: Mechanical Properties of Materials - 2


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Attempt Test: Mechanical Properties of Materials - 2 | 10 questions in 30 minutes | Mock test for Mechanical Engineering preparation | Free important questions MCQ to study Solid Mechanics for Mechanical Engineering Exam | Download free PDF with solutions
QUESTION: 1

Flow stress corresponds to

Solution:

The stress required to cause the metal to flow plastically to any given strain.

QUESTION: 2

Plasticity must be considered in designing for processes except

Solution:
QUESTION: 3

The loss of strength in compression due to overloading is known as

Solution:


(Bauschinger effect and hysteresis loop) Due to stress loading unloading, the yield stress in tension gets increased and yield stress in compression gets decreased. This decreasing of yield stress in compression is the Bauschinger effect. 

QUESTION: 4

Rupture stress is

Solution:
QUESTION: 5

The property of a material by virtue of which it can be beaten or rolled into plates is called

Solution:

it is a property of material allows it to expand in all directions without rupture. A malleable material has to be highly plastic, though it may not posses high stress. This property is of great use in processes such as forging, hot rolling, etc.

QUESTION: 6

Hardness is the resistance to

Solution:
QUESTION: 7

Which of the following factors affect the mechanical properties of a material under applied loads?

Solution:

Contents of alloys improve or decrease the hardness and strength of materials. Finer grain sizes improve the strength of the material. Imperfection and defects reduce the strength of the material. Shape, however, has little or no effect on the material.

QUESTION: 8

The change in the unit volume of a material under tension with increase in its Poisson’s ratio will

Solution:

The poisson's ratio is related to modulus of elasticity as Y=3B (1 − 2σ).
Since stress is same for Y and B, we get, dL/L = dV/3V (1 − 2σ)
⟹dV = 3V(dL/L)(1 − 2σ)
As σ is increased, dV decreases. 

QUESTION: 9

True stress-strain curve for material is plotted between

Solution:
QUESTION: 10

Consider the following statements about truestress-strain method/curve:
1. It is more sensitive to changes in both metallurgical and mechanical conditions.
2. It gives a more accurate picture of the ductility.
3. It can be correlated with stress-strain values in other tests like torsion, impact, combined stress tests etc.
4. It can be used for compression tests as well.

Which of the above statements are correct?

Solution:
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