Description

This mock test of Test: Mensuration- 2 for Banking Exams helps you for every Banking Exams entrance exam.
This contains 10 Multiple Choice Questions for Banking Exams Test: Mensuration- 2 (mcq) to study with solutions a complete question bank.
The solved questions answers in this Test: Mensuration- 2 quiz give you a good mix of easy questions and tough questions. Banking Exams
students definitely take this Test: Mensuration- 2 exercise for a better result in the exam. You can find other Test: Mensuration- 2 extra questions,
long questions & short questions for Banking Exams on EduRev as well by searching above.

QUESTION: 1

Find the volume of a cuboid whose length is 8 cm, breadth 6 cm and height 3.5 cm.

Solution:
(8×6)×3.5=48×3.5= 168.00cm cube.

QUESTION: 2

Find the volume of a cuboid whose length is 8 cm, width is 3 cm and height is 5 cm.

Solution:
Volume of cubiod =l×b×h

=8×3×5

=120cm3 .

=8×3×5

=120cm3 .

QUESTION: 3

Find the perimeter of the a square with side 4cm.

Solution:
Because the perimeter of square is 4×side

so, 4×4=16

so, 4×4=16

QUESTION: 4

Find the cube root of 140 × 2450.

Solution:

140 x 2450 = 343000

Cube root of 343000 = (343000)^{1/3} = (70^{3})^{1/3 }= 70

QUESTION: 5

A rectangular paper of width 7 cm is rolled along its width and a cylinder of radius 20 cm is formed. Find the volume of the cylinder.

Solution:

Given : A rectangular paper of width 14 cm is rolled along its width to form a cylinder.

Height of cylinder = h = 7 cm = width of the rectangular paper

And

Radius of cylinder ( Given ) = r = 20 cm

And

we know Volume of cylinder = π r^2 h , So

Volume of our given cylinder = 22/7 x 20 x 20 x 7 = 8800 cm^3

QUESTION: 6

Top surface of a raised platform is in the shape of regular octagon as shown in the figure. Find the area of the octagonal surface.

Solution:

This regular octagon can be into two trapeziums (each having height 4 m and parallel sides as 11 m and 5 m) and a rectangular part with length 11 m and breadth 5 m.

QUESTION: 7

The diagonal of a quadrilateral shaped field is 24 m and perpendicular dropped on it from the remaining opposite vertices are 6 m and 12 m. Find the area of the field.

Solution:

area=1/2×d×(h_{1}+h_{2})

=1/2×24×(12+6)

=12(18)

=216 m^{2}

QUESTION: 8

If the parallel sides of a parallelogram are 2 cm apart and their sum is 10 cm then its area is:

Solution:

QUESTION: 9

If the edge of a cube is 1 cm then which of the following is its total surface area?

Solution:
Total surface area of cube is 6*length^2

=6×1^2

=6×1

=6 cm2

=6×1^2

=6×1

=6 cm2

QUESTION: 10

Find the area of a triangle whose base is 4 cm and altitude is 6 cm.

Solution:

We know that area of triangle is equals to 1/2 base × altitude.

Here, base = 4 cm and altitude = 6 cm.

So, area = 1/2 × 4 × 6= 24 /2= 12 cm^{2}.

### Mensuration : Lecture 2

Video | 11:37 min

### NCERT Solutions(Part - 2) - Mensuration

Doc | 8 Pages

### NCERT Solutions(Part- 2)- Mensuration

Doc | 4 Pages

### Mensuration

Video | 30:30 min

- Test: Mensuration- 2
Test | 10 questions | 10 min

- Test: Mensuration- 2
Test | 10 questions | 10 min

- Test: Mensuration - 2
Test | 20 questions | 20 min

- Olympiad Test: Mensuration - 2
Test | 20 questions | 40 min

- Mensuration - MCQ 2
Test | 20 questions | 40 min