Which of the following statements is not true regarding molecular orbital theory?
Bonding molecular orbital has lower energy than the antibonding molecularorbital.
2s and 2p-atomic orbitals combine to give how many molecular orbitals?
2s-> (σ2s) (0*2s) (2)
2p -> (σ2pz) (σ*2pz)(π2px)(π*2px) (π2py) (π*2py) (6)
The conditions for the combination of atomic orbitals to form molecular orbitals are stated below. Mark the incorrect condition mentioned here.
Sigma molecular orbitals are symmetrical around the bond axis while pi molecular orbitals are not symmetrical.
The electronic configuration of carbon is Is2 2s2 2p2. There are 12 electrons in C2. The correct electronic configuration of C2 molecule is
For atoms like nitrogen and below N in atomic number have higher energy for pz -orbital, hence the configuration for C2 molecule is
(σls2)(σ*1s2) (σ2s2) (σ*2s2) (π2p2x = π2p2y)
The increasing order of energies of various molecular orbitals of N2 is given below:
σls <σ*ls <σ2s <σ*2s <π2px = π2py <σ2pz < π*2px = π*2py<σ*2pz
The above sequence is not true for the molecule
For allel ements which have atomic number more than 7(beyond nitrogen) the energy of σ2pz is lower than
π2px and π2py -orbitals.
Which of the following species has unpaired electrons?
N2, F2 and O2-2 have paired electrons
What is the order of stability of N2 and its ions?
Bond order of N2 = 3, N+2 = 2.5 N-2 = 2.5 and N22- is 2. Higher the bond order, more is the stability.
What will be the bond order of the species with electronic configuration 1s2 2s2 2p5?
Electronic configuration of atom: 1s2 2s2 2p5
M.O. configuration:
Which of the following bond orders is indication of existence of a molecule?
A molecule exists only if the bond order is positive. If bond order is zero or negative, the molecule does not exist.
Which of the following pairs will have same bond order?
F2 and O2-2 are isoelectronic
Bond order of N+2,N-2 and N2 will be
According to molecular orbital theory, which of the following will not exist?
Be2: (σ1s2) (σ*1s2) (σ2s2) (σ*2s2)
Since B.O. is zero, the molecule does not exist.
Which of the following facts regarding bond order is not valid?
Higher the bond order, higher is the bond enthalpy.
Which of the following formulae does not show the correct relationship?
Bond order ∝ Bond dissociation energy.
Fill in the blanks with the appropriate choice.
Bond order of N+2 is ___P___ while that of N2 is ___Q___ . Bond order of O+2 is ___R___ while that of O2 is ___S___ . N−N bond distance ___T___ , when N2 changes to N+2 and when O2 changes to O+2 , the O-O bond distance ___U___ .
Since N+2 has lower bond order than N2, bond length of N - N in N+2 increases .In O+2 , bond order increases form 2 to 2.5 hence , bond length decreases.
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