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Test: Molecular Orbital Theory


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Test: Molecular Orbital Theory - Question 1

Direction (Q. Nos. 1-14) This section contains 14 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. Assuming that Hund’s rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is

[IIT JEE 2010]

Detailed Solution for Test: Molecular Orbital Theory - Question 1

B2 (10 electrons)
MO electronic configuration is 

Bonding electrons = 6
Anti-bonding electrons = 4

No unpaired electron-diamagnetic

Test: Molecular Orbital Theory - Question 2

In which of the following pairs of molecules/ions both the species are not likely to exist?

Detailed Solution for Test: Molecular Orbital Theory - Question 2

Species with (zero) bond order will not exist.
Electrons in orbital

 

Test: Molecular Orbital Theory - Question 3

Among the following the maximum covalent character is shown by the compound 

Test: Molecular Orbital Theory - Question 4

Assuming (2s-2p) mixing is not operative, the paramagnetic species among the following is

[JEE Advanced 2014]

Detailed Solution for Test: Molecular Orbital Theory - Question 4

If (2s-2p) mixing is not operative, then

Test: Molecular Orbital Theory - Question 5

Select the correct statem ent about   and and O2.

Detailed Solution for Test: Molecular Orbital Theory - Question 5


 

Test: Molecular Orbital Theory - Question 6

The common features among the species CN-, CO, NO+ and N2 are

Detailed Solution for Test: Molecular Orbital Theory - Question 6


Thus, all these are isoelectronic. MO electronic configuration is

No electron unpaired - diamagnetic
Bonding electrons = 10
Anti-bonding electrons = 4
Thus, bond- order = 

Test: Molecular Orbital Theory - Question 7

According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order?

Detailed Solution for Test: Molecular Orbital Theory - Question 7

Test: Molecular Orbital Theory - Question 8

O — F and F2 can be compared in terms of

Detailed Solution for Test: Molecular Orbital Theory - Question 8


Bond energy of O — F (1.5) > F — F (1)
Thus, OF is more stable than F2 thus, (c).

Test: Molecular Orbital Theory - Question 9

Which of the following diatomic molecules would be stabilised by the removed of an electron?

Detailed Solution for Test: Molecular Orbital Theory - Question 9

A molecule is stabilised if bond-order increases, an anti-bonding electron is lost

Test: Molecular Orbital Theory - Question 10


Probability (electron charge density) of bonding and anti-bonding molecular orbitals are given.

Select the correct probability,

Detailed Solution for Test: Molecular Orbital Theory - Question 10

Electron-charge density in a bonding molecular orbital is high in the internuclear region as shown in II.
In an anti-bonding molecular orbital, it is high in parts of the molecule away from the internuclear region.

Test: Molecular Orbital Theory - Question 11

If one of the electrons in the He2 molecule is taken to the next excited state, then bond order in He2

Detailed Solution for Test: Molecular Orbital Theory - Question 11



Electron is taken to next excited state that is  hen electronic configuration is 

Number of electrons in bonding molecular orbital = 3
and in anti-bonding molecular orbital = 1
Thus, bond order = (3 - 1) /2 =1
Thus, bond order increases by 1 unit. 

Test: Molecular Orbital Theory - Question 12

If one of the electrons (1s2) of helium is taken in excited state then bond order of He2 is

Detailed Solution for Test: Molecular Orbital Theory - Question 12


Number of electrons in bonding orbital = 4 and in anti-bonding orbitai = 0

Test: Molecular Orbital Theory - Question 13

The bond energy of H2 is 436 kJ mol -1. Thus, bond energy of   is

Detailed Solution for Test: Molecular Orbital Theory - Question 13

Test: Molecular Orbital Theory - Question 14

Consider the following oxidation/reduction process,




Q. Magnetic moment does not change in 

Detailed Solution for Test: Molecular Orbital Theory - Question 14

Test: Molecular Orbital Theory - Question 15

Direction (Q. Nos. 15) This sectionis based on statement I and Statement II. Select the correct answer from the code given below.

Q. 

Statement I : N2 has a greater dissociation energy than  , where as O2 has lower dissociation energy than .

Statement II : N2 has 14 electrons while O2 has 16 electrons .

Detailed Solution for Test: Molecular Orbital Theory - Question 15


Electron from bonding molecular orbital of higher stability is lost (requires higher energy).

Electron from antibonding molecular orbital of lower stability is lost (requires lower energy).
N2 has 14 electrons and O2 has 16 electrons.
Thus, both Statements I and II are correct but Statement II is not the correct explanation of Statement I

*Multiple options can be correct
Test: Molecular Orbital Theory - Question 16

Direction (Q. Nos. 16-18) This section contains 4 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or  MORE THANT ONE  is correct.

Q. Set of species with identical bond order is/are

Detailed Solution for Test: Molecular Orbital Theory - Question 16

isoelectronic species will generally have identical bond order:

*Multiple options can be correct
Test: Molecular Orbital Theory - Question 17

One of the electrons of the highest energy level is taken to next excited state in the following diatomic species. Select the species which undergoes change in bond order? 

Detailed Solution for Test: Molecular Orbital Theory - Question 17

*Multiple options can be correct
Test: Molecular Orbital Theory - Question 18

In which of the following processes, does the value of magnetic moment change ?

Detailed Solution for Test: Molecular Orbital Theory - Question 18

(a) CO (14e), no unpaired electron, magnetic moment = 0
CO+ (13e), One electron is lost from bonding melecular orbital unpaired electron = 1, magnetic moment =
(b)  (15e) Unpaired electron = 1, magnetic moment =
(13e) Unpaired electron = 1, magnetic moment =
(c) Zn, Zn2+, unpaired electron = 0
(d) O2 (16e), unpaired electron = 2, magnetic moment =
, unpaired electron = 1, magnetic moment =

Test: Molecular Orbital Theory - Question 19

Direction (Q. Nos. 19-20) This section contains  a paragraph, each describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given options (a),(b),(c),(d)

Valence shell MO electronic configuration of a diatomic species is shown

* is for anti-bonding molecular orbital (MO).

 

Q. Bond order of this species is

Detailed Solution for Test: Molecular Orbital Theory - Question 19

Total number of electrons = 16

Number of bonding electrons = 10,
Number of anti-bonding electrons = 6,

Test: Molecular Orbital Theory - Question 20

Valence shell MO electronic configuration of a diatomic species is shown

* is for anti-bonding molecular orbital (MO).

 

Q. Divalent cation of this species

Detailed Solution for Test: Molecular Orbital Theory - Question 20

Total number of electrons = 16

Number of bonding electrons = 10, Number of anti-bonding electrons = 6,

Test: Molecular Orbital Theory - Question 21

Direction (Q. Nos. 21) Choice the correct combination of elements and column I and coloumn II  are given as option (a), (b), (c) and (d), out of which ONE option is correct.

Q. Match the conversion in Column l with the type of effect given in Column II.

Detailed Solution for Test: Molecular Orbital Theory - Question 21

Thus, (i) - (q , r)    (ii) - (q.t),
(iii) - (q,r),    (iv)- (P.s).
(v) - (q,s).

*Answer can only contain numeric values
Test: Molecular Orbital Theory - Question 22

Direction (Q. Nos. 22 and 23) This section contains 3 questions. when worked out will result in an integer from 0 to 9 (both inclusive).

Q. Total number of electrons in anti-bonding MO in (superoxide ion) is .......


Detailed Solution for Test: Molecular Orbital Theory - Question 22

 (17 electrons) has molecular orbital electronic configuration 

Underlined are anti-bonding molecular orbital Thus, seven electrons are in anti-bonding molecular orbitals.

*Answer can only contain numeric values
Test: Molecular Orbital Theory - Question 23

How many bonding MO are used in the formation of NO?


Detailed Solution for Test: Molecular Orbital Theory - Question 23

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