Test: Network Theorems (A.C.) - 1 - Electrical Engineering (EE) MCQ

# Test: Network Theorems (A.C.) - 1 - Electrical Engineering (EE) MCQ

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## 10 Questions MCQ Test GATE Electrical Engineering (EE) Mock Test Series 2025 - Test: Network Theorems (A.C.) - 1

Test: Network Theorems (A.C.) - 1 for Electrical Engineering (EE) 2024 is part of GATE Electrical Engineering (EE) Mock Test Series 2025 preparation. The Test: Network Theorems (A.C.) - 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Network Theorems (A.C.) - 1 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Network Theorems (A.C.) - 1 below.
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Test: Network Theorems (A.C.) - 1 - Question 1

### Determine VTH for the circuit external to RL in the given figure.

Detailed Solution for Test: Network Theorems (A.C.) - 1 - Question 1

Test: Network Theorems (A.C.) - 1 - Question 2

### Referring to the given circuit, how much power, in watts, is delivered to the speaker at the determined frequency if VS = 4.5 VRMS? Block Diagram: Circuit Diagram:

Detailed Solution for Test: Network Theorems (A.C.) - 1 - Question 2

To calculate the power delivered to the speaker in the given circuit, we need to consider the voltage across the speaker and the current passing through it. Let's break down the solution into the following steps:

Step 1: Determine the Voltage across the Speaker
- The voltage across the speaker can be calculated using Ohm's Law: V = I * R
- Given that VS = 4.5 VRMS and the impedance of the speaker is 8 Ω, we can calculate the voltage across the speaker as follows:
- VS = IR
- I = VS / R
- I = 4.5 / 8
- I = 0.5625 A

Step 2: Calculate the Power delivered to the Speaker
- The power delivered to the speaker can be calculated using the formula: P = V * I
- Substituting the values we calculated earlier:
- P = 4.5 * 0.5625
- P = 2.53125 W
- Converting the power to milliwatts: 2.53125 * 1000 = 2531.25 mW

Therefore, the power delivered to the speaker at the determined frequency when VS = 4.5 VRMS is 2531.25 mW, which is closest to option D: 424 mW.

Test: Network Theorems (A.C.) - 1 - Question 3

### If two currents are in the same direction at any instant of time in a given branch of a circuit, the net current at that instant.

Detailed Solution for Test: Network Theorems (A.C.) - 1 - Question 3

Correct option is B

The resultant of the currents flowing in the same direction in a particular branch must be equal to the sum of the individual currents.

For example, 3A and 5A are the currents flowing in the same direction in a branch.

Resultant current flowing though the branch Itotal​=3+5=8A

Thus option B is correct.

Test: Network Theorems (A.C.) - 1 - Question 4

Norton's theorem gives

Test: Network Theorems (A.C.) - 1 - Question 5

Referring to the given circuit, determine ZTH as seen by RL.

Test: Network Theorems (A.C.) - 1 - Question 6

Determine the frequency at which the maximum power is transferred from the amplifier to the speaker in the given figure.

Block Diagram:

Circuit Diagram:

Test: Network Theorems (A.C.) - 1 - Question 7

Referring to the given circuit, what is ZTH if R1 is changed to 220 Ω?

Test: Network Theorems (A.C.) - 1 - Question 8

Referring to the given circuit, what is VTH if VS = 12 ∠0° V?

Test: Network Theorems (A.C.) - 1 - Question 9

The two basic components of a Thevenin equivalent ac circuit are

Test: Network Theorems (A.C.) - 1 - Question 10

In Superposition theorem, while considering a source, all other current sources are?

Detailed Solution for Test: Network Theorems (A.C.) - 1 - Question 10

In Superposition theorem, while considering a source, all other current sources are open circuited. Superposition theorem is not valid for power responses. It is applicable only for computing voltage and current responses.

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