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Vth = (6)(6)/(6 + 3) or 4 V.
Rth = (3||6) + 2 or 4 ohm.
A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm-1, the power dissipated by the bulb is
V1 = (15/2)/(1/4 + 1/2 + 1/2)
In = Isc = V1/2 = 3 A.
Rn = (2||4) + 2.
Vth = (2)(3)(1)/3+3 = 1V.
Rth = 1||5 or 5/6 ohm.
After killing all source equivalent resistance is R. Open circuit voltage is v1.
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11 videos|57 docs|108 tests
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