Test: Newton Rikhman Law

# Test: Newton Rikhman Law

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## 10 Questions MCQ Test Heat Transfer | Test: Newton Rikhman Law

Test: Newton Rikhman Law for Chemical Engineering 2023 is part of Heat Transfer preparation. The Test: Newton Rikhman Law questions and answers have been prepared according to the Chemical Engineering exam syllabus.The Test: Newton Rikhman Law MCQs are made for Chemical Engineering 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Newton Rikhman Law below.
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Test: Newton Rikhman Law - Question 1

### Newton-Rikhman law is given by

Detailed Solution for Test: Newton Rikhman Law - Question 1

Regardless of the particular nature, the appropriate rate equation for the convective heat transfer is prescribed by Newton’s law of cooling.

Test: Newton Rikhman Law - Question 2

### The value of film coefficient is dependent upon (i) Boundary layer configuration (ii) Geometry and orientation of the surface (iii) Surface conditions

Detailed Solution for Test: Newton Rikhman Law - Question 2

It depends upon surface conditions i.e. roughness and cleanliness, geometry and orientation of the surface i.e. plate, tube and cylinder placed vertically or horizontally.

Test: Newton Rikhman Law - Question 3

### The convection coefficients for boiling and condensation lie in the range

Detailed Solution for Test: Newton Rikhman Law - Question 3

Convection mechanisms involving phase changes lead to important field of boiling and condensatio.

Test: Newton Rikhman Law - Question 4

Forced air flows over a convection heat exchanger in a room heater, resulting in a convective heat transfer coefficient 1.136 k W/mK. The surface temperature of heat exchanger may be considered constant at 65 degree Celsius, and the air is at 20 degree Celsius. Determine the heat exchanger surface area required for 8.8 k W of heating

Detailed Solution for Test: Newton Rikhman Law - Question 4

Q = h A (t – t f). So. A = 0.172 m2.

Test: Newton Rikhman Law - Question 5

A region of fluid motion near a plate in which temperature gradient exist is

Detailed Solution for Test: Newton Rikhman Law - Question 5

The fluid velocity decreases as it approaches the solid surface reaching to zero in the fluid layer immediately next to the surface. The thin layer of stagnated fluid is called thermal boundary layer.

Test: Newton Rikhman Law - Question 6

Thermo-physical properties of the fluid are represented by
(i) Density
(ii) Viscosity
(iii) Specific heat
(iv) Thermal conductivity
Identify the correct option

Detailed Solution for Test: Newton Rikhman Law - Question 6

The value of film coefficient is dependent upon thermos-physical properties of he fluid i.e. density, viscosity, specific heat, coefficient of expansion and thermal conductivity.

Test: Newton Rikhman Law - Question 7

A motor cycle cylinder consists of ten fins, each 150 mm outside diameter and 75 mm inside diameter. The average fin temperature is 500 degree Celsius and the surrounding air is at 20 degree Celsius temperature. Make calculations for the rate of heat dissipation from the cylinder fins by convection when motor cycle is stationary and convective coefficient is 6 W/m2K

Detailed Solution for Test: Newton Rikhman Law - Question 7

A = 0.265 m2 and Q = (6) (0.265) (500 – 20) = 763.2 W.

Test: Newton Rikhman Law - Question 8

Consider the above problem, make calculations for the rate of heat dissipation from the cylinder fins by convection when motor cycle is moving at 60 km/hr and convective coefficient is 75 W/m2 K

Detailed Solution for Test: Newton Rikhman Law - Question 8

A = 0.265 m2 and Q = (75) (0.265) (500 – 20) = 9540 W.

Test: Newton Rikhman Law - Question 9

The temperature profile at a particular location on a surface is prescribed by the identity
(t s – t) / (t s – t infinity) = (1/2) (y/0.0075) + (3/2) (y/0.0075)
If thermal conductivity of air is stated to be 0.03 W/m K, determine the value of convective heat transfer coefficient

Detailed Solution for Test: Newton Rikhman Law - Question 9

h = – k/ (t s – t infinity) [d t/d y] y = 0.

Test: Newton Rikhman Law - Question 10

Air at 20 degree Celsius flows over a flat surface maintained at 80 degree Celsius. The local heat flow at a point was measured as 1250 W/m2 .Take thermal conductivity of air as 0.028 W/m K, calculate the temperature at a distance 0.5 mm from the surface

Detailed Solution for Test: Newton Rikhman Law - Question 10

Temperature at 0.5 mm from the surface is 80 + (d t/d y) y = 0 (0.0005) = 57.682 degree celsius.

## Heat Transfer

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## Heat Transfer

58 videos|70 docs|85 tests