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This mock test of Test : Perimeter And Area - 1 for Class 5 helps you for every Class 5 entrance exam.
This contains 10 Multiple Choice Questions for Class 5 Test : Perimeter And Area - 1 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

A carpet is laid on the floor of a room 8 m by 5 m, leaving a border 0.5 m wide all round it. What is the perimeter of the carpet?

Solution:

QUESTION: 2

What is the area of the given figure?

Solution:

Number of unit squares = 23

Now, 1 = 1 sq. unit

Area of figure = 23 square units

QUESTION: 3

The figure is made up of 8 identical rectangles, Find the total area of the shaded figure.

Solution:

After rearranging the given figure, we get the new figure.

Area of 1 small rectangle = 10x5 = 50

sq. cm Number of shaded rectangles ^ 4

Total shaded area = 4x50 = 200 sq. cm

QUESTION: 4

In the given figure, DE = HI = AL = 2 cm and LK = IJ = HG = EF = 5 cm. Find the perimeter of the given figure (in cm).

Solution:

We have,

BC = AL + KJ + IH + GF + ED

= (2 + 2 + 2 + 2 + 2)cm = 10 cm

Perimeter of the given figure

= (7 +10+7 + 2 +5+ 2 +5+ 2 +5+ 2 +5+ 2)cm 54cm

QUESTION: 5

ACEG is a square. AB is 1/2 of AC. What is the perimeter of the square?

Solution:

We have, AB = 1/2 x AC

6cm = 1 x AC = > AC = 6 x 2 = 12 cm

Side of square -= 12 cm

So, perimeter of square 12 x 4= 48 cm

QUESTION: 6

What is the area of the shaded figure?

Solution:

Area of 1 small square = (2x2)cm^{2}

= 4 cm^{2}

Number of shaded square ^ 14

Shaded area = 14 x 4 = 56 cm^{2}

QUESTION: 7

Perimeter of any regular figure is _______.

Solution:

QUESTION: 8

The perimeter of a rectangular picture is 160 cm. It is 30 cm wide. How long is it?

Solution:

Perimeter = 160 cm

Breadth = 30 cm

2(Length + Breadth) = 160 cm

2(Length + 30 cm) = 160 cm

=> Length +30 cm= 80 cm

=> Length = (80 - 30) cm = 50 cm

QUESTION: 9

Find the total shaded area of the figure made up of identical squares.

Solution:

Area of 1 small square = (3x3)cm^{2}

= 9cm^{2}

Number of shaded squares =19

Shaded area = 19 x 9 = 171cm^{2}

QUESTION: 10

Find the perimeter of the given figure.

Solution:

Perimeter of the given figure

=(2+ 3+1+10+5+ 4 +17+ 4 +5+6+ 4 +7)

cm

= 68cm

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