Test: Phase & Group Velocity


12 Questions MCQ Test Electromagnetic Fields Theory | Test: Phase & Group Velocity


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This mock test of Test: Phase & Group Velocity for Electronics and Communication Engineering (ECE) helps you for every Electronics and Communication Engineering (ECE) entrance exam. This contains 12 Multiple Choice Questions for Electronics and Communication Engineering (ECE) Test: Phase & Group Velocity (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Phase & Group Velocity quiz give you a good mix of easy questions and tough questions. Electronics and Communication Engineering (ECE) students definitely take this Test: Phase & Group Velocity exercise for a better result in the exam. You can find other Test: Phase & Group Velocity extra questions, long questions & short questions for Electronics and Communication Engineering (ECE) on EduRev as well by searching above.
QUESTION: 1

In a waveguide, which of the following condition is true always?

Solution:

Answer: c
Explanation: The phase velocity is always greater than the speed of light in waveguides. This implies the group velocity is small.

QUESTION: 2

The term cos θ is given by 2.5. Find the phase velocity.

Solution:

Answer: c
Explanation: The phase velocity is given by Vp = c cos θ. On substituting for cos θ = 2.5 and the speed of light, we get the phase velocity as 7.5 x 108 m/s.

QUESTION: 3

The cut off wavelength and the guided wavelength are given by 0.5 and 2 units respectively. Find the wavelength of the wave.

Solution:

Answer: a
Explanation: The cut off wavelength and the guided wavelength are related as (1/λ)2 = (1/λc)2 + (1/λg)2. On substituting for λc = 0.5 and λg = 2, we get λ = 0.48 units.

QUESTION: 4

The cut off wavelength of the rectangular waveguide in dominant mode with dimensions 6 cm x 4 cm is

Solution:

Answer: a
Explanation: The cut off wavelength in the dominant mode is given by λc = 2a/m, where a is the broad wall dimension. On substituting for m = 1 and a = 6cm, we get the cut off wavelength as 12cm.

QUESTION: 5

The product of the phase and the group velocities is given by the

Solution:

Answer: d
Explanation: The product of the phase and the group velocities is given by the square of the speed of the light. Thus Vp x Vg = c2 is the relation.

QUESTION: 6

The phase velocity of a wave having a group velocity of 6 x 106 is (in order of 108 m/s)

Solution:

Answer: d
Explanation: We know that the phase and the group velocities are given by Vp x Vg = c2. On substituting for Vg = 6 x 106 and the speed of light, we get Vp = 150 x 108 m/s.

QUESTION: 7

The group velocity of a wave with a phase velocity of 60 x 109 is (in 106 order) 

Solution:

Answer: a
Explanation: We know that the phase and the group velocities are given by Vp x Vg = c2. On substituting for Vp = 60 x 109 and the speed of light, we get Vg = 1.5 x 106 m/s.

QUESTION: 8

The phase velocity of a wave having a phase constant of 4 units and a frequency of 2.5 x 109 radian/sec is (in 108 order)

Solution:

Answer: c
Explanation: The phase velocity and the phase constant are related by Vp = ω/βg. On substituting for ω = 2.5 x 109 and β = 4, we get the phase velocity as 6.25 units.

QUESTION: 9

The guided wavelength and the phase constant are related by

Solution:

Answer: a
Explanation: The guided wavelength and the phase constant are related by 2π/βg = λg, where βg is the guided phase constant and λg is the guided wavelength.

QUESTION: 10

The phase velocity refers to a group of waves and the group velocity refers to a single wave. State true/false.

Solution:

Answer: b
Explanation: The phase velocity refers to a single wave and the group velocity refers to a group of waves.

QUESTION: 11

The phase and group velocities does not depend on which of the following?

Solution:

Answer: d
Explanation: The phase and the group velocities are directly related by the frequency, wavelength and the phase constant. It is independent of the attenuation constant.

QUESTION: 12

The distance between two successive points in a waveguide is the

Solution:

Answer: c
Explanation: The distance between two successive points in a waveguide is equal to half of the guided wavelength.

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