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If probability of drawing a spade from a wellshuffled pack of playing cards is ¼ then the probability that of the card drawn from a wellshuffled pack of playing cards is ‘not a spade’ is
Probability of the sample space is
Sum of all probabilities is equal to
Let a sample space be S = {X_{1}, X_{2}, X_{3}} which of the fallowing defines probability space on S ?
Let P be a probability function on S = {X_{1} , X_{2} , X_{3}} if P(X_{1})= ¼ and P(X_{3}) = 1/_{3} then P (X_{2}) is equal to
The chance of getting a sum of 10 in a single throw with two dice is
Option (b) 1 /2 is correct.
Explanation:
{ There are a total of 36 combinations on throw of two dice.
The sum of 10 could be obtained as :
(6+4, 4+6, 5+5) that is in 3 ways.
Therefore, the required probability here is : 3 / 36 = 1/ 12
=> 1/ 12
The chance of getting a sum of 6 in a single throw with two dice is
P (B/A) defines the probability that event B occurs on the assumption that A has happened
The complete group of all possible outcomes of a random experiment given an ________ set of events.
When the event is ‘certain’ the probability of it is
The classical definition of probability is based on the feasibility at subdividing the possible outcomes of the experiments into
Two unbiased coins are tossed. The probability of obtaining ‘both heads’ is
Two unbiased coins are tossed. The probability of obtaining one head and one tail is
Two unbiased coins are tossed. The probability of obtaining both tail is
Two unbiased coins are tossed. The probability of obtaining at least one head is
When 3 unbiased coins are tossed. The probability of obtaining 3 heads is
Correct Answer : d
Explanation :
Total no. Of outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, TTT
No. Outcomes of all heads: 1
Prob. Of all heads = no. Of outcomes of all heads/ total no. Of outcomes
i.e (1/8)
When unbiased coins are tossed. The probability of getting both heads or both tails is
Two dice with face marked 1, 2, 3, 4, 5, 6 are thrown simultaneously and the points on the dice are multiplied together. The probability that product is 12 is
A bag contain 6 white and 5 black balls. One ball is drawn. The probability that it is white is
Probability of occurrence of at least one of the events A and B is denoted by
Probability of occurrence of A as well as B is denoted by
Which of the following relation is true ?
If events A and B are mutually exclusive, the probability that either A or B occurs is given by
The probability of occurrence of at least one of the 2 events A and B (which may not be mutually exclusive) is given by
If events A and B are independent, the probability of occurrence of A as well as B is given by
For the condition P(AB)= P(A)P(B) two events A and B are said to be
The conditional probability of an event B on the assumption that another event A has actually occurred is given by
In a throw of coin what is the probability of getting tails.
Total cases = [H,T]  2
Favourable cases = [T] 1
So probability of getting tails = 1/2
Demand of products per day for three days are 21, 19, 22 units and their respective probabilities are 0.29, 0.40, 0.35. profit per unit is $0.50 then expected profits for three days are
If P (A)= 1, P(B)= 1, the events A & B are
If events A and B are independent then
A card is drawn at random from a wellshuffled deck of playing cards. Find the probability that the card drawn is a card of spade or an ace.
There are 52 cards in total.
Hence, total Outcomes =52
Probability of the card drawn is a card of spade or an Ace:
Total cards of Spade =13
Total Aces =4
Number of Aces of Spade =1
Therefore,
Probability of the card drawn is a card of spade or an Ace:
13/52 + 4/52  1/52 = 16/52 = 4/13
When a die is tossed, the sample space is
Find the expectation of a random variable X?
If events A and B are independent and P(A)= 2/3 , P(B)= 3/5 then P(A+B)is equal to
The expected no. of head in 100 tosses of an unbiased coin is
A and B are two events such that P(A)= 1/_{3}, P(B) = ¼, P(A+B)= 1/_{2}, than P(B/_{A}) is equal to
Probability mass function is always
What is the probability of getting an even number when a dice is thrown?
The sample space when a dice is rolled, S = (1, 2, 3, 4, 5, and 6)
So, n (S) = 6 E is the event of getting an even number.
So, n (E) = 3
Probability of getting an even number P (E) = Total number of favorable outcomes/Total number of outcomes
n(E) / n(S) = 3/6 = ½
The sum of probability mass function is equal to
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