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Test: Properties Of Semiconductors - Mechanical Engineering MCQ


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15 Questions MCQ Test - Test: Properties Of Semiconductors

Test: Properties Of Semiconductors for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Properties Of Semiconductors questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Properties Of Semiconductors MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Properties Of Semiconductors below.
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Test: Properties Of Semiconductors - Question 1

 How does a semiconductor behave at absolute zero?

Detailed Solution for Test: Properties Of Semiconductors - Question 1

A semiconductor is a solid which has the energy band similar to that of the insulator. It acts as an insulator at absolute zero.

Test: Properties Of Semiconductors - Question 2

Semiconductor acts as an insulator in the presence of impurities. True or false?

Detailed Solution for Test: Properties Of Semiconductors - Question 2

When the temperature is raised or when impurity is added, their conductivity increases. Conductivity is inversely proportional to temperature.

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Test: Properties Of Semiconductors - Question 3

How is the resistance of semiconductor classified?

Detailed Solution for Test: Properties Of Semiconductors - Question 3

Semiconductors have negative temperature co-efficient. The reason for this is, when the temperature is increased, a large number of charge carriers are produced due to breaking of covalent bonds and hence these electrons move freely and gives rise to conductivity.

Test: Properties Of Semiconductors - Question 4

What are the charge carriers in semiconductors?

Detailed Solution for Test: Properties Of Semiconductors - Question 4

In conductors, electrons are charge carriers. But in semiconductors, both electrons and holes are charge carriers and will take part in conduction.

Test: Properties Of Semiconductors - Question 5

Which of the following is known as indirect band gap semiconductors?

Detailed Solution for Test: Properties Of Semiconductors - Question 5

The elemental semiconductor is made up of single element from the fourth column elements such as Germanium. Here recombination takes place takes place via traps. It is called indirect bad gap semiconductors.

Test: Properties Of Semiconductors - Question 6

Which column elements are combined to make compound semiconductors?

Detailed Solution for Test: Properties Of Semiconductors - Question 6

The compound semiconductors are made by combining the third and fifth column elements. Such as GaAs are made by combining third and fifth column elements.

Test: Properties Of Semiconductors - Question 7

 Compound semiconductors are also known as direct bad gap semiconductors. True or false?

Detailed Solution for Test: Properties Of Semiconductors - Question 7

In compound semiconductors, recombination takes place directly and its energy difference is emitted in the form of photons in the visible or infrared range. Hence the compound semiconductors are also knows as direct band gap semiconductors.

Test: Properties Of Semiconductors - Question 8

 How is charge carriers produced in intrinsic semiconductors?

Detailed Solution for Test: Properties Of Semiconductors - Question 8

Impure semiconductors in which the charge carriers are produced due to impurity atoms are called extrinsic semiconductors. They are obtained by doping an intrinsic semiconductor with impurity atoms.

Test: Properties Of Semiconductors - Question 9

What type of material is obtained when intrinsic semiconductor is doped with pentavalent impurity?

Detailed Solution for Test: Properties Of Semiconductors - Question 9

 N-type semiconductor is obtained by doping an intrinsic semiconductor with pentavalent impurity atoms.

Test: Properties Of Semiconductors - Question 10

What type of material is obtained when an intrinsic semiconductor is doped with trivalent impurity?

Detailed Solution for Test: Properties Of Semiconductors - Question 10

 P-type semiconductor is obtained by doping an intrinsic semiconductor with trivalent impurity.

Test: Properties Of Semiconductors - Question 11

 Which method can be used to distinguish between the two types of carriers?

Detailed Solution for Test: Properties Of Semiconductors - Question 11

 When a conductor carrying current is placed in a transverse magnetic field, an electric field is produced inside the conductor in a direction normal to both the current and the magnetic field. This phenomenon is known as Hall Effect.

Test: Properties Of Semiconductors - Question 12

 Find the resistance of an intrinsic Ge rod cm long, 1mm wide and 1mm thick at 300K.

Detailed Solution for Test: Properties Of Semiconductors - Question 12

Conductivity of an intrinsic semiconductor = nieeh)
Conductivity = 2.32
Resistance = ρl/A = l/(conductivy ×A)
Resistance = 4310 ohm

Test: Properties Of Semiconductors - Question 13

A semiconducting crystal 12mm long, 5mm wide and 1mm thick has a magnetic flux density of 0.5Wb/m2 applied from front to back perpendicular to largest faces. When a current of 20mA flows length wise through the specimen, the voltage measured across its width is found to be 37μV. What is the Hall coefficient of this semiconductor?

Detailed Solution for Test: Properties Of Semiconductors - Question 13

Hall coefficient = (VH b)/(IH B)
Hall coefficient = 3.7×10-6 m3/C

Test: Properties Of Semiconductors - Question 14

The intrinsic carrier density at room temperature in Ge is 2.37×1019/m3. If the electron and hole mobilities are 0.38 and 0.18 m2/Vs respectively. Calculate its resistivity.

Detailed Solution for Test: Properties Of Semiconductors - Question 14

 Conductivity = nieeh)
Conductivity = 2.12352/ohm m
Resistivity = 1/Conductivity
Resistivity = 0.4709ohm m

Test: Properties Of Semiconductors - Question 15

A silicon plate of thickness 1mm, breadth 10mm and length 100mm is placed in a magnetic field of 0.5 Wb/m2 acting perpendicular to its thickness. If 10-3 A current flows along its length, calculate the Hall voltage developed, if the Hall coefficient is 3.66×104 m3/Coulomb.

Detailed Solution for Test: Properties Of Semiconductors - Question 15

VH = (RH IH B)/t
VH = 1.83×10-3 Volts

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