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Quality factor is also known as voltage magnification because the voltage across the capacitor or inductor in resonance condition is equal to Q times the source voltage.
At resonance condition, voltage across the capacitor and inductor is _________ the source voltage.
In resonance condition the voltage across the capacitor and inductor is greater than the source voltage because the voltage across the capacitor or inductor in resonance condition is equal to Q times the source voltage.
What is the voltage across the capacitor when the source voltage is 100V and the Q factor is 10.
We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage =10*100=1000V.
Find the Q factor when the voltage across the capacitor is 1000V and the source voltage is 100V.
We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage. Vc=QV. Substituting the values from the given question, we get Q=10.
Find the source voltage when the voltage across the capacitor is 1000V and the Q factor is 10.
We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage. Vc=QV. Substituting the values from the given question, we get V=100V.
What is the voltage across the inductor when the source voltage is 200V and the Q factor is 10.
We know that voltage across the inductor in resonance condition is equal to Q times the source voltage =10*200=2000V.
Find the Q factor when the voltage across the indictor is 2000V and the source voltage is 100V.
We know that voltage across the inductor in resonance condition is equal to Q times the source voltage. VL=QV. Substituting the values from the given question, we get Q=20.
Find the source voltage when the voltage across the inductor is 2000V and the Q factor is 20.
We know that voltage across the inductor in resonance condition is equal to Q times the source voltage. VL=QV. Substituting the values from the given question, we get V=100V.
What happens to the voltage across the capacitor when the Q factor increases?
We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage. Hence as the Q factor increases, the voltage across the capacitor also increases.
What happens to the voltage across the inductor when the Q factor decreases?
We know that voltage across the inductor in resonance condition is equal to Q times the source voltage. Hence as the Q factor decreases, the voltage across the inductor also decreases.
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