Column A: The task is to find out how many three-digit even numbers can be made using all the prime numbers less than 10 without repetition.
Column B: The task is to find out how many two-digit numbers can be made using all the prime numbers less than 7 without repetition.
Let's start by identifying the prime numbers less than 10 for Column A: they are 2, 3, 5, and 7. Since we're looking to form even numbers and even numbers must end with an even digit, 2 must be the last digit. For the first two digits, we can use 3, 5, and 7 in any order, which gives us 3! (3 factorial) possibilities.
For Column B, we identify the prime numbers less than 7: they are 2, 3, and 5. Since we are forming two-digit numbers without repetition, we can choose any of the three digits for the first place and any of the remaining two digits for the second place.
Let's calculate the exact numbers for both columns.
The calculations show that both Column A and Column B have the same number of possibilities, which is 6. Therefore, the correct answer is:
Option C: Both are equal.