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CA Foundation Exam  >  CA Foundation Tests  >  Quantitative Aptitude for CA Foundation  >  Test: Ratio And Proportion, Indices, Logarithms - 2 - CA Foundation MCQ

Test: Ratio And Proportion, Indices, Logarithms - 2 - CA Foundation MCQ


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30 Questions MCQ Test Quantitative Aptitude for CA Foundation - Test: Ratio And Proportion, Indices, Logarithms - 2

Test: Ratio And Proportion, Indices, Logarithms - 2 for CA Foundation 2024 is part of Quantitative Aptitude for CA Foundation preparation. The Test: Ratio And Proportion, Indices, Logarithms - 2 questions and answers have been prepared according to the CA Foundation exam syllabus.The Test: Ratio And Proportion, Indices, Logarithms - 2 MCQs are made for CA Foundation 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Ratio And Proportion, Indices, Logarithms - 2 below.
Solutions of Test: Ratio And Proportion, Indices, Logarithms - 2 questions in English are available as part of our Quantitative Aptitude for CA Foundation for CA Foundation & Test: Ratio And Proportion, Indices, Logarithms - 2 solutions in Hindi for Quantitative Aptitude for CA Foundation course. Download more important topics, notes, lectures and mock test series for CA Foundation Exam by signing up for free. Attempt Test: Ratio And Proportion, Indices, Logarithms - 2 | 40 questions in 40 minutes | Mock test for CA Foundation preparation | Free important questions MCQ to study Quantitative Aptitude for CA Foundation for CA Foundation Exam | Download free PDF with solutions
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 1
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Division of Rs. 750 into 3 parts in the ratio 4 : 5 : 6 is

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 2
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The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio 7 : 8 : 9. Their present ages are

Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 2

their 10years ago age be 7x,8x,9x
so their current age be 7x+10,8x+10,9x+10
7x+10+8x+10+9x+10=120
24x+30=150
24x=120
x=5
present age= 7x+10,8x+10,9x+10
                   =7(5)+10,8(5)+10,9(5)+10
                   =45,50,55

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Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 3
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The numbers 14, 16, 35, 42 are not in proportion. The fourth term for which they will be in proportion is

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 4
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If x/y = z/w, implies y/x = w/z, then the process is called
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 5
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If p/q = r/s = p–r/q–s, the process is called
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 6
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If a/b = c/d, implies (a+b)/(a–b) = (c+d)/(c–d), the process is called
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 7
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If u/v = w/p, then (u–v)/(u+v) = (w–p)/(w+p). The process is called
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 8
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12, 16, x, 20 are in proportion. Then find x
Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 8

Concept used:

If given a : b : : x : c

then x is called the third proportion.

It can be calculated as,

a/b = x/c

⇒ x = ac/b

Calculations:

12 : 16 : : x : 20

then,

x = (12 × 20)/16

⇒ x = 15

∴ third proportion = 30

 

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 9
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4, *, 9, 13½ are in proportion. Then * is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 10
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The mean proportional between 1.4 gms and 5.6 gms is
Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 10

Let 1.4 gms, x gms and 5.6 gms be in continuous proportion.

(Mean proportional terms)^2 = Product of extremes.

Therefore x^2 = 1.4 x 5.6

therefore x^2 = 7.84

therefore x= 2.8 gms.

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 11
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Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 12
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Two numbers are in the ratio 3 : 4; if 6 be added to each terms of the ratio, then the new ratio will be 4 : 5, then the numbers are
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 13
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Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 14
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Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 14

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 15
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if  then  (b-c)x + (c-a)y+(a-b)z is 
Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 15

Let X=(b+c-a);y=(c+a-b);z=(a+b-c)

=(b-c)(b+c-a)+(c-a)(c+a-b)+(a-b)(a+b-c)

=b^2-c^2-ab+ac+c^2-a^2-bc+ab+a^2-b^2-ac+bc

=0

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 16
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4x–1/4 is expressed as
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 17
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The value of 81/3 is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 18
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The value of 2 × (32) 1/5 is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 19
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The value of 4/(32)1/5 is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 20
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The value of (8/27)1/3 is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 21
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2½ .4¾ is equal to
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 22
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 has simplified value equal to 
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 23
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xa–b × xb–c × xc–a is equal to
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 24
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The value of  is equal to 
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 25
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{(33)2 × (42)3 × (53)2} / {(32)3 × (43)2 × (52)3} is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 26
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Which is True ?
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 27
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If x1/p = y1/q = z1/r and xyz = 1, then the value of p+q+r is
Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 27

x1/p=y1/q=z1/r=k (say)

⇒ x = kp,y = kq,z = kr

xyz=1 (given)

kp.kq.kr=1

k(p+q+r)=1.

k(p+q+r)=k0

p+q+r = 0

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 28
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The value of ya–b × yb–c × yc–a × y–a–b is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 29
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The True option is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 30
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The simplified value of 16x–3y2 × 8–1x3y–2 is
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