Test: Relative Velocity in Two Dimensions
10 Questions MCQ Test Physics for ACT | Test: Relative Velocity in Two Dimensions
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A body is moving with a constant acceleration of 11î + 2ĵ, starting from î + ĵ. What will be the position of the body after 10s?
The body’s displacement is given by s = (1/2)at2. Therefore, after putting in the values, we get, s = (1/2)(11î + 2ĵ)*102 = 550î + 100ĵ. The body initially starts from î + ĵ. Hence, the final position is = initial position + displacement = 551î + 101ĵ.
A body is moving with a constant velocity of 4î + 3ĵ, starting from the origin. What will be the position of the body after 10s?
The body’s displacement is given by s = vt. The body starts from the origin hence, the total displacement is the final position of the body. Therefore, after putting in the values, we get, s = (4î + 3ĵ)*10 = 40î + 30ĵ.
Velocity of a man is 25 units in the positive X direction and 75 units in negative Y direction starting from the origin. Velocity of a woman is 25 units in the positive Y direction and 75 units in the negative X direction starting from the origin. What is the relative velocity of the man with respect to the woman?
The velocity of the man is 25î – 75ĵ and that of the woman is -75î + 25ĵ. Relative velocity = velocity of man – velocity of woman = 100î – 100ĵ.
The velocity of a car A is to 5î + 11ĵ. The velocity of another car B is 11î + 5ĵ. What is the relative velocity of B with respect to A?
The formula for calculating relative velocity of a body with respect to another body is- relative velocity = Velocity vector of A – Velocity vector of B. Hence, here, the relative velocity = velocity of B – velocity of A = 6î – 6ĵ.
A body is moving with a constant acceleration of 4î + 3ĵ, starting from the origin. What will be the position of the body after 5s?
The body’s displacement is given by s = (1/2)at2. The body starts from the origin hence, the total displacement is the final position of the body. Therefore, after putting in the values, we get, s = (1/2)(4î + 3ĵ)*52 = 50î + 37.5ĵ.
Velocity of a dog is 15 units in the positive X direction and 3 units in positive Y direction starting from the origin. Velocity of a pig is 7 units in the positive Y direction and 17 units in the positive X direction starting from the origin. What is the relative velocity of the dog with respect to the pig?
The velocity of the man is 15î+3ĵ and that of the woman is 17î + 7ĵ. Relative velocity = velocity of dog – velocity of pig = -2î – 4ĵ.
The velocity of a car A is to 5î. The velocity of another car B is 22î – 7ĵ. What is the relative velocity of A with respect to B?
The formula for calculating relative velocity of a body with respect to another body is- relative velocity = Velocity vector of A – Velocity vector of B. Hence, here, the relative velocity = velocity of B – velocity of A = -17î + 7ĵ.
When two bodies move uniformly towards each other, the distance decrease by 6 m/s. If both the bodies moves (as above) in the same direction with the same speed, the distance between them increases by 4 m/s. Then the speed of the two bodies are
Concept:
A) When two bodies move uniformly in opposite direction, the velocities gets added up.
B) When two bodies move uniformly in same direction, the velocities gets subtracted.
Calculation:
Given:
Let one bodies be A and B, and theor speed be V and U respectively.
As per the problem;
VA + VB = 6 ------(i)
VA - VB = 4 ------(ii)
Adding eq (i) and eq (ii)
2VA = 10
∴ VA = 5 m/s
Similarly
VA + VB = 6
5 + VB = 6
∴ VB = 1 m/s
At a metro station, a girl walks up a stationary escalator in time t1 . If she remains stationary on the escalator, then the escalator take her up in time t2. The time taken by her to walk up on the moving escalator will be
In the situation of a stationary escalator and moving girl velocity,
In the situation of stationary girl and moving escalator velocity,
If both escalator and girl keep moving then distance,
L = (V + V1) t3 ----(3)
Where t3 is time to cover that distance when both girl and the escalator keep moving.
Using equations (1), (2), and (3) we get:
Then, time is taken 
If S = 3t2 - 5t + 7 find initial velocity.
Formula Used:
Velocity = s/t
Here, S is displacement and t is time
For instantaneous velocity, it expressed as dS/dt
Application:
We have,
S = 3t2 - 5t + 7
Hence,
Instantaneous velocity = dS/dt = (6t - 5)
initial velocity will be found at t = o
Hence,
V|initial = (6 × 0 - 5) = - 5
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