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A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the current in the circuit.
XL=2*pi*f*L= 10ohm. Therefore the total impedance =sqrt(R^{2}+XL^{2})=12.2ohm.
V=IZ, therefore 100/12.2= 8.2A.
A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.
φ=tan^{1}(XL/R)=55.1
Since this is an inductive circuit, the current will lag, hence φ= 55.1.
A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the voltage across the resistor.
XL=2*pi*f*L= 10ohm. Therefore the total impedance =sqrt(R^{2}+XL^{2})=12.2ohm.
V=IZ, therefore 100/12.2= 8.2A.
Voltage across resistor= 8.2*7=57.4V.
A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the voltage across the inductor.
XL=2*pi*f*L= 10ohm. Therefore the total impedance =sqrt(R^{2}+XL^{2})=12.2ohm.
V=IZ, therefore 100/12.2= 8.2A.
Voltage across resistor= 8.2*7=57.4V.
Voltage across inductor =100VR= 42.6V.
A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a x V 50Hz sinusoidal supply. The current in the circuit is 8.2A. Calculate the value of x.
XL=2*pi*f*L= 10ohm. Therefore the total impedance =sqrt(R^{2}+XL^{2})=12.2ohm.
V=IZ, Therefore V=12.2*8.2=100V.
Which, among the following, is the correct expression for φ.
Form the impedance triangle, we get tanφ= XL/R.
Hence φ=tan^{1} (XL/R).
For an RL circuit, the phase angle is always ________
For a series resistance and inductance circuit the phase angle is always a negative value because the current will always lag the voltage.
Form the voltage triangle, we get cosφ= VR/V.
Hence φ=cos^{1}VR/V.
An RL network is a network which consists of a resistor which is connected in series to an inductor.
At DC, the inductor acts as short circuit because the inductive resistance is zero. The frequency of a DC circuit is 0. The inductive resistance=(2*pi*f*L). Therefore, if the frequency is 0, the inductive resistance is zero and it acts as an short circuit.
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