The coordinates of a point A, where AB is diameter of a circle whose centre is (2,3) and B is (1, 4), are:
Let the coordinates of point A is (x, y)
Now, AB is the diameter of circle. So, midpoint of AB is the center of the circle.
Given, center O(2,3) and B is (1,4).
So, by using midpoint formula, we get:
If is the midpoint of the linesegment joining the points A (6, 5) and B (2,3) then the value of a is
Applying distance formula
The ratio in which the point P(3,y) divides the line segment joining the points A(5,4) and B(2,3) is
The coordinates of the point which divide the line segment joining P (2, 2) and Q (2, 8) into two equal parts are:
The midpoint of the line segment joining P(2,8) and Q(6,4) is
Determine the ratio in which the line 2x+y4 = 0 divides the line segment joining the points A (2,2) and B (3, 7)
The mid point of the line segment joining A(2a,4) and B(2,3b) is M (1,2a + 1). The values of a and b are
The ratio in which the xaxis divides the segment joining A(3,6) and B(12,3) is
The ratio in which the line 2x+y4 = 0 divides the line segment joining A(2,2) and B(3,7) is
If A (1,2) , B (4,y), c (x,6) and D (3,5) are the vertices of a parallelogram taken in order then the values of x and y are:
The ratio in which the line segment joining A(3,4) and B(2,1) is divided by the yaxis is
The line segment joining A(2,9), and B(6,3) is a diameter of a circle with centre C. The coordinates of C are
The coordinates of the point which divides the line segment joining points A(5,2) and B(9,6) in the ratio 3:1 are
The ratio in which (4,5) divides the line segment joining the points (2,3) and (7,8) is
Origin divides the join of points (1,1) and (2,2) externally in the ratio
We have external section formula as
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