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Test: Sequence & Series - 1 - CAT MCQ


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10 Questions MCQ Test - Test: Sequence & Series - 1

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Test: Sequence & Series - 1 - Question 1

The maximum value of the sum of the AP 50, 48, 46, 44,…50, 48, 46, 44,… is

Detailed Solution for Test: Sequence & Series - 1 - Question 1

For maximum value of the given sequence to n terms, when the nth term is either zero or the
smallest positive number of the sequence
ie., 50 + (n − 1)(−2) = 0 ⇒ n = 26
Therefore, S26 = 26/2 (50 + 0) = 26 × 25 = 650

Test: Sequence & Series - 1 - Question 2

A bouncing ball loses just 25% of its energy on impact with the ground. If the ball is dropped from a height of 30m, find the total distance travelled by the ball before it comes to rest. Neglect air resistance.

Detailed Solution for Test: Sequence & Series - 1 - Question 2

Initial height is 30m, after the first bounce, the height reached is 3/4(30). After the second bounce, the height reached = 3*3/4*4(30).

Total distance travelled = 30 + 3/4(30)*2 + 3/4(3/4(30))*2 + …

= 30 + 3/4(30)*2/(1-3/4) = 210m

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Test: Sequence & Series - 1 - Question 3

Find the sum of the series 82, 113, 144, … ,609 ?

Detailed Solution for Test: Sequence & Series - 1 - Question 3

This is an arithmetic series with first term equal to 82 and common difference equal to 31
Let the number of digits be equal to n.
So,  82 + (n-1) 31 = 609
or, n = 18
So, the sum equals 18/2 ∗(82+609) = 9∗691 = 6219

Test: Sequence & Series - 1 - Question 4

From the first 25 natural numbers, how many arithmetic progressions of 6 terms can be formed such that common difference of the AP is a factor of the 6th term.

Detailed Solution for Test: Sequence & Series - 1 - Question 4

Let the first term of the AP be a and the common difference be d.
The sixth term of the series will be a + 5d
Given that d should be a factor of a + 5d
=> a + 5d is divisible by d
=> a should be divisible by d
So the required cases are
d = 1, a = 1, 2, 3.......20
d= 2 , a = 2, 4, 6.......14
d = 3, a = 3, 6, 9
d= 4, a = 4
So the required number of AP’s are 20 + 7 + 3 + 1 = 31

Test: Sequence & Series - 1 - Question 5

The ratio of the 8th and 17th terms of an AP is 5 : 11. The product of the first and the sixth terms of the AP is 176. If the AP has only negative terms in the series, find the sum of the first 200 terms of the series.

Detailed Solution for Test: Sequence & Series - 1 - Question 5

Let the first term be a and the common difference be d. We have, (a + 7d)/(a + 16d) = 5/11.
Solving this, we get d = 2a. Product of the first and sixth terms is a (a + 5d) = a(a + 10 a) = 11a2 = 176 ⇒ a = + - 4
Since the series has only negative terms, a=-4 and d=-8.
Sum of the first 200 terms = (200/2)(2*-4 + 199*- 8) = -160000

Test: Sequence & Series - 1 - Question 6

A sequence is such that in any set of four consecutive terms, the sum of first and third term is equal to the sum of second and fourth term. If the third term is equal to 5, 26th term is equal to 9 and the sum of first 18 terms is equal to 58, find the first term.

Detailed Solution for Test: Sequence & Series - 1 - Question 6

Let the first term be a, second term be x and the third term be c.
Fourth term = a + c - x
Fifth term = a
Sixth term = x
In this way pattern will repeat.
26th term = 2nd term = x = 9
c = 5
2(a + c)*4 + a + x = 58
9a + 8c + x = 58
9a + 40 + 9 = 58
a = 1

Test: Sequence & Series - 1 - Question 7

Find the sum of first 99991 odd numbers?

Detailed Solution for Test: Sequence & Series - 1 - Question 7

The sum of the first 99991 odd numbers is 999912 = 9998200081

Test: Sequence & Series - 1 - Question 8

In a row of children, Bali is seventh from the left and Moti is fourth from the right. When Bali and Moti exchange positions, Bali will be fifteenth from the left. What will be Moti’s position from the right?

Detailed Solution for Test: Sequence & Series - 1 - Question 8

Since, Bali’s count from the left goes up by 8, Moti’s count from the right would go down by 8 too. Option (d) is correct.

Test: Sequence & Series - 1 - Question 9

Which of the following cannot be a number of the series ….64, 125, 216, 343, 512 …..? 

Detailed Solution for Test: Sequence & Series - 1 - Question 9

All the numbers in the series are perfect cubes. 999 is not a cube of any natural number. Hence, Option (d) does not belong to the series.

Test: Sequence & Series - 1 - Question 10

Find out the missing term: 0, 3, 8, 15, 24, 35, 48?

Detailed Solution for Test: Sequence & Series - 1 - Question 10

The series is following the pattern +3, +5, +7, +9, +11, +13 and hence the next term should be 48 + 15 = 63. Answer is option (b).

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