Description

This mock test of Test: Sequences And Series - 1 for SSC helps you for every SSC entrance exam.
This contains 10 Multiple Choice Questions for SSC Test: Sequences And Series - 1 (mcq) to study with solutions a complete question bank.
The solved questions answers in this Test: Sequences And Series - 1 quiz give you a good mix of easy questions and tough questions. SSC
students definitely take this Test: Sequences And Series - 1 exercise for a better result in the exam. You can find other Test: Sequences And Series - 1 extra questions,
long questions & short questions for SSC on EduRev as well by searching above.

QUESTION: 1

Which number is wrong in the given series?

12439, 23549, 34659, 45769

Solution:

Here we need to find the wrong number in 12439, 23549, 34659, 45769

as we will add the digits of every number

12439 : 1+2+3+4+9 = 19

23549 : 2+3+5+4+9 = 23

34659 : 3+4+6+5+9 = 27

45769 : 4+5+7+6+9 = 31

As we can see that in every case the sum of digits of a number is a prime number except in case of 34659 and hence 34659 is the odd one out.

QUESTION: 2

Find the missing number :

2, 10, 20, 32, 46, ?

Solution:

let the missing number be y

10 – 2 = 8

20 – 10 = 10

32 – 20 = 12

46 – 32 = 14

as we can see that difference is getting increased by 2 and hence

y – 46 = 16

y = 62

QUESTION: 3

What will come in place of the question mark (?) in the series?

3, 8, 27, 112, (?), 3396

Solution:

Let the missing term be y

here the sequence is 3, 8, 27, 112, y, 3396

here the pattern is :

8 = 3 x 2 + 2

27 = 8 x 3 + 3

112 = 27 x 4 + 4

so from the highlighted pattern , we can say that

y = 112 x 5 + 5 = 565

QUESTION: 4

If 1 + 4=9, 2 + 8=18, 3+6 = 15 then 7 + 8 = ?

Solution:

Here we are given :

1 + 4=9

2 + 8=18

3+6 = 15

So if the number is , x + y then it is equal to [(x+y) + y]

here we need to calculate value of 7 + 8 = [(7 + 8) + 8] = 23

QUESTION: 5

Find the wrong number in the series from the given alternatives.

17, 36, 53, 68, 83, 92

Solution:

The terms in the series are 17 + (17+19) + (17+19+17) + (17+19+17+15) + ( 17+19+15+15) + (17+19+15+13+11) .

Each term adds the odd number which precedes the one added to the previous term, except for the fifth term.

The correct sequence would be 17,36,53,68,81,92.

Hence Option C is the correct answer.

QUESTION: 6

Find the wrong number in the series. 6, 9, 15, 22, 51, 99

Solution:

9 -6 =3

15 -9 =6

22 -15 =7

51 -22 =29

99 -51 =48

So Ignoring the difference between the terms where one of the terms is 22 all other differences are multiple of 3

So 22 is the wrong term and the correct series would have been

9 -6 = 3 x 1

15 -9 = 3 x 2

27 -15 = 3 x 4

51 -27 = 3 x 8

99 -51 = 3 x 16

So 22 is the wrong term.

QUESTION: 7

Find out the set of numbers amongst the four sets of numbers given in the

alternatives which is most like the set given in the question.

Given Set : (8, 56, 72)

Solution:

(8, 56, 72)

follows the pattern

(8 , 8 x 7 , 8 x 9 )

So (6. 42, 54) is similar to (8, 56, 72)

as it follows the pattern

(6 , 6 x 7 , 6 x 9 )

QUESTION: 8

Which of the given letter groups follows the same principle on which the numbers are arranged in the given number group ?

(5, 8, 13, 20, 29)

Solution:

The Series follows the pattern

5

5+3 =8

8+5 =13

13 +7 =20

20+9 = 29

So the option representing the correct letter group must follow the same pattern

So the letter series is

A

A+3 = D

D +5 =I

I +7 = P

P + 9 =Y

So the letter series is ADIPY

QUESTION: 9

Find out the wrong number in the sequence

102, 101, 98, 93, 86, 74, 66, 53

Solution:

The Series follows pattern

102

102 -1 =101

101 -3 =98

98 -5 =93

93 -7 =86

Since 1,3,5 and 7 are subtracted in order to get the next term

So 7 +2 =9

should be subtracted in order to get next term

So next term should be

86 -9 =77

77 -11 =66

66-13 =53

So option C is correct.

QUESTION: 10

Based on the given data, estimate the number of ‘Television buyers’ for the year 1990.

1982 1984 1986 1988 1990

447 458 489 540 ?

Solution:

Number of television Buyers in 1982 = 447

Number of Television buyers in 1984 = 458 (447+11)

Number of Television buyers in 1986 = 489 (458+ 11 +20)

Number of Television buyers in 1988 = 540 (489 + 11 +20 +20 )

Number of Television buyers in 1990 = 611 (540 + 11 +20 +20 + 20 )

### Introduction to series - Sequences & Series

Video | 02:43 min

### Notes : Sequences & Series

Doc | 13 Pages

### Sequences and Series (part 1) - Calculus, Mathematics

Video | 09:49 min

### Sequences n series

Doc | 26 Pages

- Test: Sequences And Series - 1
Test | 15 questions | 30 min

- Test: Sequences And Series - 1
Test | 10 questions | 10 min

- Test: Sequences And Series (CBSE Level) - 1
Test | 25 questions | 25 min

- Test: Special Sequences And Series
Test | 10 questions | 10 min

- Sequences And Series Of Real Numbers -1
Test | 20 questions | 60 min