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Test: Sequences And Series- 2 - Commerce MCQ


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Test: Sequences And Series- 2 - Question 1

If the numbers a, b, c, d, e form an A.P. then the value of a – 4b + 6c – 4d + e is

Test: Sequences And Series- 2 - Question 2

The sum of all non-reducible fractions with the denominator 3 lying between the numbers 5 and 8 is

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Test: Sequences And Series- 2 - Question 3

The next term of the sequence 1, 1, 2, 4, 7, 13,…. Is

Test: Sequences And Series- 2 - Question 4

An A.P. consists of n (odd) terms and its middle term is m. Then the sum of the A.P. is

Test: Sequences And Series- 2 - Question 5

The terms equidistant from a given term of an A.P. are multiplied together, then the difference of the successive terms of the series so formed are in

Test: Sequences And Series- 2 - Question 6

If the numbers a, b, c are in A.P., b, c, d are in G.P. and c, d , e are in H.P., then a, c, e are in

Test: Sequences And Series- 2 - Question 7

If x, y, z are in A.P., then (x + 2y – z) (x + z – y) (z + 2y – x) is equal to

Test: Sequences And Series- 2 - Question 8

If a, b , c are in A.P. and also 1/a, 1/b, 1/c are A. P., then

Test: Sequences And Series- 2 - Question 9

The sum of terms equidistant from the beginning and end in A.P. is equal to

Test: Sequences And Series- 2 - Question 10

Sum of first 5 terms of an A.P. is one fourth of the sum of next five terms. If the first term = 2, then the common difference of the A.P. is

Test: Sequences And Series- 2 - Question 11

The first, second and last terms of an A.P. are a, b and 2 a. The number of terms in the A.P. is

Test: Sequences And Series- 2 - Question 12

The sum of all the two-digit numbers is

Test: Sequences And Series- 2 - Question 13

Sum of all 2 digit odd numbers is

Detailed Solution for Test: Sequences And Series- 2 - Question 13

All two-digit odd positive numbers are 11, 13, 15, 17, ...., 99. which are in AP with a=11,d=2,l = 99
Let the number of terms be n.
an=99
a+(n−1)d=99
11+(n−1)×2=99
n=45
Sum of n terms is given by Sn= n/2(a+l)
Sn= 45/2(11+99) = 2475

Test: Sequences And Series- 2 - Question 14

The number of terms common to the two A.P.s 2 + 5 + 8 + 11 + … + 98 and 3 + 8+ 13 + 18+ 23 + … + 198

Detailed Solution for Test: Sequences And Series- 2 - Question 14

For first A.P 2+5+8+11+......+98
a=2,an=98,d=3
an=a+(n−1)d
98=2+(n−1)3
98=2+3n−3
3n=99
n=33
Number of term =33
For first A.P 3+8+13+18+......+198
a=3,an=198,d=5
an=a+(n−1)d
198=3+(n−1)5
198=3+5n−5
5n=200
n=40
No of terms =40
Common terms=40−33=7

Test: Sequences And Series- 2 - Question 15

The values of x for which the solutions of the equation cos θ = x, θ ≥ 0 form an A.P. are

Test: Sequences And Series- 2 - Question 16

If a ∈ R, then the roots of the equation tan x = a are in

Test: Sequences And Series- 2 - Question 17

The values of ‘a’ for which the roots of the equation sin x = a in A.P. are

Test: Sequences And Series- 2 - Question 18

The sum of first four terms of an A. P. is 56 and sum of last four terms is 112. If the first term is 11, then the number of terms is

Detailed Solution for Test: Sequences And Series- 2 - Question 18

Test: Sequences And Series- 2 - Question 19

The ratio of the 7th to the (n –1)th mean between 1 and 31, when n arithmetic means are inserted between them, is 5 : 9. The value of n is

Test: Sequences And Series- 2 - Question 20

The sum of first n terms of the series 1 – 1 + 1 – 1 + … is

Test: Sequences And Series- 2 - Question 21

If a, b, c, d , e are in G. P., then e/c equals

Test: Sequences And Series- 2 - Question 22

The product of first n odd terms of a G.P. whose middle term is m is

Test: Sequences And Series- 2 - Question 23

The fourth term of a G. P. is 2, then product of first 7 terms is

Test: Sequences And Series- 2 - Question 24

If three positive numbers a, b, c are in G. P. then log a, log b, log c are in

Test: Sequences And Series- 2 - Question 25

The nth term of the sequence 5 + 55 + 555 + …. is

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