Signal Classification & Properties - Free MCQ Practice Test with solutions,

All of the other functions have a periodic element in them, which means the function attains the same value after a period of time, which should not occur for a monotonic function.

The period of a signal is the length of one complete cycle of the signal. To find the period of the given signal, we need to find the length of time it takes for the signal to repeat itself.

The signal x(t) = sin(18pit + 78 deg) can be rewritten as x(t) = sin(2pit + 78/180*pi). The frequency of a signal is the number of cycles per second, and is related to the period by the equation T = 1/f, where T is the period and f is the frequency. In this case, the frequency of the signal is f = 18/2 = 9 cycles/second. Therefore, the period of the signal is T = 1/f = 1/9 seconds/cycle = 1⁄9 seconds/cycle.

The correct answer is therefore 1⁄9.

reduces to 1 – 2t, which is a strictly decreasing function.

Time period = 2*pi/(50)pi = 1/25 = 0.04s

Consider limit at t tending to infinity, we obtain 1 for both cases.

If the bounded function, is say y = 2, then the integral ceases to hold. Similarly, if it is just the block square function, it is finite. Hence, it depends upon the spread of the signal on either side. If the spread is finite, the integral will be finite.

Put the limits as t tends to infinity and as t tends to zero.

For an odd function, f(-x) = -f(x), thus the integrals will cancel each other, giving zero.

Differentiate the function for an optima, put it to zero, we will obtain t = 1.5 as the required instant.

Though sin(t) is a periodic function, exp(-t) is not a periodic function, thus leading to non-periodicity.