1 Crore+ students have signed up on EduRev. Have you? 
Which of the following statements is incorrect regarding significant figures?
The power of 10 is irrelevant to the determination of significant figures.
The value of resistance is 10.845 Ω and the current is 3.23 A. On multiplying, we get the potential difference is 35.02935 V. The value of potential difference in terms of significant figures would be
The final result should be 3 significant figures.
A cube has a side of length 1.2 x 10^{2}m. Its volume upto correct significant figures is
Here
Length of the cube, L = 1.2 x 10^{2} m
Volume of the cube, V = (1.2 x 10^{2}m)^{3} = 1.728 x 10^{6} m^{3}
As the result can have only two significant figures, therefore, on rounding off, we get, V = 1.7 x 10^{6} m^{3}
The radius of a sphere is 1.41cm. Its volume to an appropriate number of significant figures is
Radius of the sphere, r = 1.41cm
(3 significant figures)
Volume of the sphere,
= 11.736 cm^{3}
Rounded off upto 3 significant figures = 11.7 cm^{3}.
The mass of a box measured by a grocer's balance is 2.3 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box. The total mass of the box is:
Here, mass of the box, m = 2.3 kg
Mass of one gold piece, m_{1} = 20.15 g = 0.02015 kg
Mass of other gold piece, m_{2} = 20.17 g = 0.02017 kg
∴ Total mass = m + m_{1} + m_{2}
= 2.3 kg + 0.02015 kg + 0.02017 kg = 2.34032 kg
As the result is correct only upto one place of decimal, therefore, on rounding off, we get
Total mass = 2.3 kg
The mass of a box measured by a grocer's balance is 2.3 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box.
What is the difference in the masses of the pieces?
Difference in masses
= m_{2}  m_{1} = 20.17 g  20.15 g
= 0.02 g (correct upto two places of decimal)
The numbers 3.845 and 3.835 on rounding off to 3 significant figures will give
The number 3.845 rounded off to three significant figures becomes 3.84 since the preceding digit is even. On the other hand, the number 3.835 rounded off to three significant figures becomes 3.84 since the preceding digit is odd.
The respective number of significant figures for the numbers 6.320, 6.032, 0.0006032 are
According to the rules of significant figures 6.320 has four significant figures.
6.032 has four significant figures. 0.0006032 has four significant figures.
The number of significant figures in the numbers 4.8000 x 10^{4} and 48000.50 are respectively
As per rule of significant figures, 4.8000 x 10^{4} has 5 significant figures and 48000.50 has 7 significant figures.
A body travels uniformly a distance of (13.8 ± 0.2) m in a time (4.0 ± 0.3) s. Its velocity with error limits is
Here, s = (13.8 ± 0.2) m, t = (4.0 ± 0.3)s
∴ veliocity, v = s/t = 13.8/4.0 = 3.45 m s^{−1}
(Rounded off to first place of decimal)
= 0.0865
or Δv = v × 0.0865 = 3.45 × 0.0865
= 0.3087.
∴ velocity =(3.5 ± 0.3) m s^{−1}.
126 videos464 docs210 tests

Use Code STAYHOME200 and get INR 200 additional OFF

Use Coupon Code 
126 videos464 docs210 tests









