Test: Sinusoidal Steady‐State Analysis - 2

# Test: Sinusoidal Steady‐State Analysis - 2

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## 10 Questions MCQ Test Network Theory (Electric Circuits) | Test: Sinusoidal Steady‐State Analysis - 2

Test: Sinusoidal Steady‐State Analysis - 2 for Electrical Engineering (EE) 2022 is part of Network Theory (Electric Circuits) preparation. The Test: Sinusoidal Steady‐State Analysis - 2 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Sinusoidal Steady‐State Analysis - 2 MCQs are made for Electrical Engineering (EE) 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Sinusoidal Steady‐State Analysis - 2 below.
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Test: Sinusoidal Steady‐State Analysis - 2 - Question 1

### The circuit is as shown in fig. P1.7.17-18 Q.i2(t) = ?

Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 1  Test: Sinusoidal Steady‐State Analysis - 2 - Question 2

### I x = ? Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 2  Test: Sinusoidal Steady‐State Analysis - 2 - Question 3

### Vx = ? Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 3

Let Vo be the voltage across current source Test: Sinusoidal Steady‐State Analysis - 2 - Question 4

Determine the complex power for the given values in question.
Q. P = 269 W, Q = 150 VAR (capacitive)

Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 4

S = P - jQ = 269 - j150 VA

Test: Sinusoidal Steady‐State Analysis - 2 - Question 5

Determine the complex power for the given values in question.
Q. Q = 2000 VAR, pf = 0.9 (leading)

Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 5  Test: Sinusoidal Steady‐State Analysis - 2 - Question 6

Determine the complex power for the given values in question.
Q. S = 60 VA, Q = 45 VAR (inductive)

Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 6  Test: Sinusoidal Steady‐State Analysis - 2 - Question 7

Determine the complex power for the given values in question.
Q. Vrms = 220 V, P = 1 kW, |Z| = 40 Ω (inductive)

Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 7  Test: Sinusoidal Steady‐State Analysis - 2 - Question 8

Determine the complex power for the given values in question.
Q. Vrms = 21∠ 200V, Vrms = 21∠200V, I rms = 8.5∠-500A

Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 8 = 61+ j167.7VA

Test: Sinusoidal Steady‐State Analysis - 2 - Question 9

Determine the complex power for the given values in question.
Q. Vrms = 120∠ 300V, Z = 40 + j 80Ω

Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 9 Test: Sinusoidal Steady‐State Analysis - 2 - Question 10

Vo = ? Detailed Solution for Test: Sinusoidal Steady‐State Analysis - 2 - Question 10  ## Network Theory (Electric Circuits)

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## Network Theory (Electric Circuits)

23 videos|21 docs|27 tests