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Test: Sinusoidal Steady State Analysis - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test - Test: Sinusoidal Steady State Analysis

Test: Sinusoidal Steady State Analysis for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Sinusoidal Steady State Analysis questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Sinusoidal Steady State Analysis MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Sinusoidal Steady State Analysis below.
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Test: Sinusoidal Steady State Analysis - Question 1

 i(t) = ?​

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Test: Sinusoidal Steady State Analysis - Question 2

Vc(t) = ?​

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Test: Sinusoidal Steady State Analysis - Question 3

 Vc(t) = ?​

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Test: Sinusoidal Steady State Analysis - Question 4

 i(t) = ?​

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Test: Sinusoidal Steady State Analysis - Question 5

In the bridge shown, Z1 = 300 ohm, Z2 = 400 – j300 ohm, Z3 = 200 + j100 ohm. The Z4 at balance is

Detailed Solution for Test: Sinusoidal Steady State Analysis - Question 5

Use Z1 x Z4 = Z2 x Z3.

Test: Sinusoidal Steady State Analysis - Question 6

Circuit for Q.6 and Q.7

Q. ​i1(t) = ?

Test: Sinusoidal Steady State Analysis - Question 7

 i2(t) = ?

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Test: Sinusoidal Steady State Analysis - Question 8

In a two element series circuit, the applied voltage and the resulting current are v(t) = 60 + 66 sin (1000t) V, i(t) = 2.3sin (1000t + 68.3) 3 A. The nature of the elements would be

Detailed Solution for Test: Sinusoidal Steady State Analysis - Question 8

RC circuit causes a positive shift in the circuit.

Test: Sinusoidal Steady State Analysis - Question 9

 P = 269 W, Q = 150 VAR (capacitive). The power in the complex form is

Detailed Solution for Test: Sinusoidal Steady State Analysis - Question 9

S = P – jQ.

Test: Sinusoidal Steady State Analysis - Question 10

Q = 2000 VAR, pf = 0.9 (leading). The power in complex form is

Detailed Solution for Test: Sinusoidal Steady State Analysis - Question 10

 Use cos T = 0.9 or T = 25.84 degrees.
Q = S sin T or S = 4588.6 VA
p = S cos T or P = 0.9 X 4588.6 4129.8 VA.

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