Test: Soil Mechanics- 1

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Test: Soil Mechanics- 1 - Question 1

If the plasticity index of a soil is 45%, then the soil will be:

A.
non-plastic
B.
very highly plastic
C.
low plastic
D.
medium plastic

Detailed Solution for Test: Soil Mechanics- 1 - Question 1

Plasticity index (PI) is the range of water content over which the soil remains in the plastic state. Mathematically defined as,

Plasticity Index = Liquid Limit (w_L) – Plastic Limit (w_p)

Test: Soil Mechanics- 1 - Question 2

Consider the following statements. The incorrect statement is:

A.
The water content has a range from 0% to 100%.
B.
The degree of saturation has ranged from 0% to 100%.
C.
The porosity cannot be greater than 100%.
D.
The void ratio of soil can be greater than 1.

Detailed Solution for Test: Soil Mechanics- 1 - Question 2

Water content is the ratio of the mass of water to the mass of solids. It can be greater than 100%.
The degree of saturation has ranged from 0% to 100%.
The porosity cannot be greater than 100%.
The void ratio of soil can be greater than 1.

Test: Soil Mechanics- 1 - Question 3

The term ‘Loess’ indicates those soils which are

1. Uniformly graded

2. Poorly graded

3. Made up of more than 50% sand size particles

4. Made up of more than 50% of silt particles

5. These are transported by winds

Which of the above statements are correct:

A.
2,3 & 5
B.
1,4 & 5
C.
2 & 4
D.
1 & 3

Detailed Solution for Test: Soil Mechanics- 1 - Question 3

Loess is an Aeolian Sediment i.e. transported by winds.
These contain fine particles like silt and clay (typically in the 20–50 micrometer size range).
Loess is uniformly graded soil. It is usually homogeneous and highly porous and is traversed by vertical capillaries that permit the sediment to fracture and form vertical bluffs.

Test: Soil Mechanics- 1 - Question 4

Match List – I (Type of soil) with List-II (Mode of transportation and deposition) and select the correct answer using the codes given below the lists:

A.
A - 1 B - 2 C - 3 D - 4
B.
A - 3 B - 2 C - 1 D - 4
C.
A - 3 B - 2 C - 4 D - 1
D.
A - 1 B - 3 C - 2 D - 4

Detailed Solution for Test: Soil Mechanics- 1 - Question 4

Lacustrine soil: Soil which is deposited from suspension in fresh still water of the lakes is known as Lacustrine soil. Lacustrine deposits are sedimentary rock formations which formed in the bottom of ancient lakes.

Alluvial Soil: Soil which is been deposited from suspension in running water is known as Alluvial soil. It is transported soil formed by physical wheathering.

Aeoline Soil: Soil which is formed due to transportation by wind is known as Aoeline soil. It is also a transported soil.

Marine soil: Soil which is deposited from the suspension in sea water is known as marine soil.

Test: Soil Mechanics- 1 - Question 5

In wet soil mass, air occupies 1/6 of its volume and water occupies 1/3 of its volume. The void ratio of the soil is

A.
0.25
B.
0.5
C.
1.00
D.
1.50

Detailed Solution for Test: Soil Mechanics- 1 - Question 5

Voids ratio: It is defined as the ratio of the total volume of voids to the volume of solids in a given soil mass.

Void ratio, e = V_v/ V_s

e > 0, voids ratio has no upper limit

V_v = air void (Va) + water filled voids (Vw)
Calculation:

Given,

V_a = 1/6 of V

V_w = 1/3 of V

V_v = Va + Vw = V/2

Test: Soil Mechanics- 1 - Question 6

The given figure indicate the weights of different pycnometers:

The specific gravity of the solids is given by

Detailed Solution for Test: Soil Mechanics- 1 - Question 6

Specific gravity of solids is the ratio of weight of given volume of solids to the weight of equivalent volume of water at 4° C.

Specific gravity is usually reported at 27°C and determined using pycnometer. It is given by

W₁= Mass of empty volume of pycnometer

W₂ = Mass of pycnometer + Mass of moist sample

W₃ = Mass of pycnometer + soil + water

W₄ = Mass of pycnometer full of water

G_s = Specific gravity of soil solids

*Answer can only contain numeric values

Test: Soil Mechanics- 1 - Question 7

The following data are given for soil:

• Porosity: n = 0.4

• The specific gravity of the soil solids: G_s = 2.68

• Moisture content: w = 12%

Determine the mass of water in kg to be added to 10 m³ of soil for full saturation.

Detailed Solution for Test: Soil Mechanics- 1 - Question 7

Total volume of soil, V = 10 m³

∴ V_V = 0.4 × 10 = 4m³

Volume of solids, V_s = V – V_V = 10 – 4 = 6 m³

Mass of solids, W_s = V_s G_s Y_w = 6 × 2.68 × 1000 = 16080 kg

Moisture content = 0.12

So, Mass of water = 0.12 × 16080 = 1929.6 kg

Volume of water = 1929.6/1000 = 1.929 m³

So, phase diagram can be shown as

For full saturation, the amount of air has to be replaced by water.

So, water to be added = 2.071 × 1000 = 2071 kg

Test: Soil Mechanics- 1 - Question 8

The water content of a soil sample is found to be 35%. If the percentage of air voids present in the soil sample is 5%. Then compute dry unit weight and air content of the soil sample when the void ratio of the soil sample is 0.65.

Take specific gravity of soil solids and unit weight of water to be 2.70 and 10 kN/m³.

A.
22.09 kN/m³ and 5%
B.
13.19 kN/m³ and 12.70%
C.
13.19 kN/m³ and 20%
D.
22.09 kN/m³ and 10%

Detailed Solution for Test: Soil Mechanics- 1 - Question 8

Dry unit weight is given by

η_a = 0.05

G = 2.70

ω = 0.35

η_d = 13.19 kN/m³

η_a = a_cη

η → porosity

a_c → aircontent

a_c = 0.1269
a_c = 12.70%

*Answer can only contain numeric values

Test: Soil Mechanics- 1 - Question 9

A fully saturated clay has a water content of 40% and unit weight 19 kN/m³. After oven drying the dry density of the soil becomes 18 kN/m³. The shrinkage limit for the soil sample is ______%. (Take γw=γw=10 kN/m³)

Detailed Solution for Test: Soil Mechanics- 1 - Question 9

And, e s_r = wG

⇒ e × 1 = 0.40 G

⇒ G = 2.97
Shrinkage limit, w_s=
Where, G_m = Mass specific gravity at dry state

*Answer can only contain numeric values

Test: Soil Mechanics- 1 - Question 10

The soil has to be excavated from a borrow-pit which has a density of 1.12 gm/cc with a water content of 12% to fill a land. The soil is compacted to a density of 1.32 gm/cc with water content 20%. Find the volume of soil to be excavated in m³ for 1000 m³ volume of the fill?

Detailed Solution for Test: Soil Mechanics- 1 - Question 10

Dry density of soil at excavation site,

∴ Volume of excavated soil =
= 1000 × 1.1/1
= 1100 m³

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10 Questions MCQ Test GATE Civil Engineering (CE) 2023 Mock Test Series | Test: Soil Mechanics- 1

If the plasticity index of a soil is 45%, then the soil will be:

Consider the following statements. The incorrect statement is:

The term ‘Loess’ indicates those soils which are

1. Uniformly graded

2. Poorly graded

3. Made up of more than 50% sand size particles

4. Made up of more than 50% of silt particles

5. These are transported by winds

Which of the above statements are correct:

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Test: Soil Mechanics- 1

10 Questions MCQ Test GATE Civil Engineering (CE) 2023 Mock Test Series | Test: Soil Mechanics- 1

If the plasticity index of a soil is 45%, then the soil will be:

Consider the following statements. The incorrect statement is:

The term ‘Loess’ indicates those soils which are 1. Uniformly graded 2. Poorly graded 3. Made up of more than 50% sand size particles 4. Made up of more than 50% of silt particles 5. These are transported by winds Which of the above statements are correct:

GATE Civil Engineering (CE) 2023 Mock Test Series

Up next

Top Courses for Civil Engineering (CE)

GATE Civil Engineering (CE) 2023 Mock Test Series

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Up next

Download free EduRev App

The term ‘Loess’ indicates those soils which are

1. Uniformly graded

2. Poorly graded

3. Made up of more than 50% sand size particles

4. Made up of more than 50% of silt particles

5. These are transported by winds

Which of the above statements are correct: