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Test: Solid State - 3 - Chemistry MCQ


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30 Questions MCQ Test Physical Chemistry - Test: Solid State - 3

Test: Solid State - 3 for Chemistry 2024 is part of Physical Chemistry preparation. The Test: Solid State - 3 questions and answers have been prepared according to the Chemistry exam syllabus.The Test: Solid State - 3 MCQs are made for Chemistry 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Solid State - 3 below.
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Test: Solid State - 3 - Question 1

For a face centered cubic lattice, the miller indices for the first Bragg’s (smallest Bragg angle):

Test: Solid State - 3 - Question 2

A crystal has the lattice parameters a ≠ b ≠ c and α = β = γ = 900. The crystal system is:

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Test: Solid State - 3 - Question 3

A metal crystallizes in face-centered cubic lattice with a lattice parameter of 4.20 Å. The shortest atom to atom contact distance in the lattice is:

Detailed Solution for Test: Solid State - 3 - Question 3

 In a face-centered cubic (FCC) lattice, atoms touch along the face diagonal. The face diagonal is equal to √2 times the lattice parameter. Therefore, the shortest atom-to-atom contact distance is calculated as follows: 4.20 Å / √2 = 2.97 Å. Hence, the correct answer is option b.

Test: Solid State - 3 - Question 4

Molybdenum crystallizes in a bcc-structure with unit cell dimensions of 0.314 nm. Considering the atomic mass of molybdenum to be 96, its density (in kg m–3) is in the range of:

Test: Solid State - 3 - Question 5

For a simple cubic crystal lattice, the angle between the [201] plane and the xy plane is:

Test: Solid State - 3 - Question 6

For a simple cubic lattice, the ratio between the unit cell length and the separation of two adjacent parallel crystal planes can NOT have a value of:

Test: Solid State - 3 - Question 7

The unit cell of diamond can be obtained from the unit cell of:

Test: Solid State - 3 - Question 8

The rank of a cubic unit cell is 4. The type of cell is:

Test: Solid State - 3 - Question 9

The defect that results when electrons are trapped in an ionic crystal lattice in place of an anion valancy is known as:

Test: Solid State - 3 - Question 10

Iron (II) oxide, FeO, crystal has a cubic structure and each edge of the unit cell is 5.0 Å. Taking density of the oxide as 4.0 g cm–3. Calculate the no. of Fe2+ and O2– ions present in each unit cell.

Test: Solid State - 3 - Question 11

Calculate the miller indices of crystal planes which cut through the crystal axis at (2a, –3b, –3c):

Test: Solid State - 3 - Question 12

Calcium fluoride crystallizes in fluorite structure. The co-ordination no. for the cation and anion is respectively:

Test: Solid State - 3 - Question 13

The atomic radius (in cm) of an element with a body centred cubit unit cell of molecular weight 137.3 and density 3.62 g cm–3 is:

Test: Solid State - 3 - Question 14

Which one of the following plane will show allowed reflection for any FCC:

Test: Solid State - 3 - Question 15

There are two crystal lattice A and B

A: Diffracts from (200) and (111) plane but not from (110)
B: Diffracts from (110) and (100) plane but not from (111)

Test: Solid State - 3 - Question 16

A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is

Test: Solid State - 3 - Question 17

The percentage of void in BCC lattice is:

Test: Solid State - 3 - Question 18

The second order brags diffraction from the (100) planes of a cubic crystal is equivalent to:

*Multiple options can be correct
Test: Solid State - 3 - Question 19

Which of the following crystals have 8:8 coordination:

*Multiple options can be correct
Test: Solid State - 3 - Question 20

Which of the following crystals have 6:6 coordination:

Detailed Solution for Test: Solid State - 3 - Question 20

⟶ NH4I and MgO crystallizes in rock salt structure (NaCl(NaCl Type)Type) where NH+4 and Mg+2 occupies all octahedral voids and I and O2− forms FCC lattice having coordination number 6:6

⟶ MnO also have 6:6 coordination as Mn+2 forms FCC lattice and O2− occupies all tetrahedral voids. 

 (Inverse of NaCl structure)

⟶ ZnS have 4:4 coordination as Zn+ occupies alternate tetrahedral voids and O2− forms FCC lattice.

*Multiple options can be correct
Test: Solid State - 3 - Question 21

Which of the following crystals have 4:4 coordination:

*Multiple options can be correct
Test: Solid State - 3 - Question 22

Which of the following statement(s) is (are) correct:

*Multiple options can be correct
Test: Solid State - 3 - Question 23

The correct statement(s) regarding defects in solids is (are):

*Multiple options can be correct
Test: Solid State - 3 - Question 24

If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m fraction of octahedral holes occupied by aluminium ions and n fraction of tetrahedral holes occupied by magnesium ions, m and n, respectively are:

*Multiple options can be correct
Test: Solid State - 3 - Question 25

The correct statement(s) for cubic close packed (ccp) three dimensional structure is (are):

*Multiple options can be correct
Test: Solid State - 3 - Question 26

Which of the following statements is/are correct:

*Multiple options can be correct
Test: Solid State - 3 - Question 27

Select write statement(s)

*Answer can only contain numeric values
Test: Solid State - 3 - Question 28

Numerical Answer type (Q. No. 28-30)

Silver (atomic weight = 108 g mol–1) has a density of 10.5 g cm–3. The no. of silver atoms on a surface of area 10–12 m2 can be expressed in scientific rotation as Y × 10x. The value of x is…..:


*Answer can only contain numeric values
Test: Solid State - 3 - Question 29

The no. of particle present in octahedral void in ZnS (Blend) structure is:


*Answer can only contain numeric values
Test: Solid State - 3 - Question 30

The empty space in hcp unit cell is?


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