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Test: Third law, Heat transfer - JEE MCQ
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10 Questions MCQ Test Chemistry for JEE Main & Advanced - Test: Third law, Heat transfer
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Test: Third law, Heat transfer - Question 1
Fixed mass of an ideal gas contained in a 24.63 L sealed rigid vessel at 1 atm is heated from −73∘C to 27∘C. Calculate change in gibb's energy if entropy of gas is a function of temperature as S = 2 + 10−2 T(J/K):(Use 1 atm L = 0.1 kJ)
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Test: Third law, Heat transfer - Question 2
For the reaction taking place at certain temperature 
if equilibrium pressure is 
bar then 
would be
if equilibrium pressure is bar then would be
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Test: Third law, Heat transfer - Question 3
Standard Gibb's free energy change for isomerization reaction cis-2-pentene ⇌ trans − 2 -pentene is −3.67 kJ/mol at 400 K. If more trans-2pentene is added to the reaction vessel, then
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Test: Third law, Heat transfer - Question 4
The dissolution of 
in water is endothermic yet it dissolves in water spontaneously. Which one of the following best explains this behaviour?
in water is endothermic yet it dissolves in water spontaneously. Which one of the following best explains this behaviour?
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Test: Third law, Heat transfer - Question 5
What is the free energy change for the conversion of 1 mole of water into steam at 
. The heat of vaporization 
of water of 
is 
. The entropy change is 
.
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Test: Third law, Heat transfer - Question 6
The favourable conditions for a spontaneous reaction are
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Test: Third law, Heat transfer - Question 7
Find the value of the equilibrium constant (K) of a reaction at 300 K, when standard Gibbs free energy change is −25 kJ mol−1 ? (Consider R = 8.33Jmol−1 K−1)
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?
Test: Third law, Heat transfer - Question 8
In a thermodynamic process, fixed mass of a gas is changed in such a manner that the gas release 
of heat and 
of work was done on the gas. If the initial internal energy of the gas was 
, the final internal energy will be
Detailed Solution for Test: Third law, Heat transfer - Question 8
heat absorbed by gas 
work done by gas.
Test: Third law, Heat transfer - Question 9
If for a given substance melting point is 
and freezing point is 
, then correct variation shown by, graph between entropy change and temperature is
and freezing point is , then correct variation shown by, graph between entropy change and temperature is
Detailed Solution for Test: Third law, Heat transfer - Question 9
and 
represent the same temperature. Hence 
is a correct choice.
Test: Third law, Heat transfer - Question 10
When 
of ice at 
melts to water at 
, the resulting change in its entropy, taking latent heat of ice to be 
, is
Detailed Solution for Test: Third law, Heat transfer - Question 10
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