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Thermodynamics (Chapter Test - Medical) - Class 12 MCQ


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20 Questions MCQ Test - Thermodynamics (Chapter Test - Medical)

Thermodynamics (Chapter Test - Medical) for Class 12 2024 is part of Class 12 preparation. The Thermodynamics (Chapter Test - Medical) questions and answers have been prepared according to the Class 12 exam syllabus.The Thermodynamics (Chapter Test - Medical) MCQs are made for Class 12 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Thermodynamics (Chapter Test - Medical) below.
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Thermodynamics (Chapter Test - Medical) - Question 1

Reaction,

According to this, heat of formation of HI will be

Detailed Solution for Thermodynamics (Chapter Test - Medical) - Question 1
Given delta h is for 2 moles... so for 1 mole divide it by 2... hence d is correct
Thermodynamics (Chapter Test - Medical) - Question 2

The work done by a closed system in a reversible process is always ___ that done in an irreversible process.

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Thermodynamics (Chapter Test - Medical) - Question 3

In which of the following neutralization reactions, the heat of neutralization will be highest ?

Thermodynamics (Chapter Test - Medical) - Question 4

The enthalpies of combustion of C(graphite) and C(diamond) are —393.5 and —395.4 kJ/mol respectively. The enthalpy of conversion of C(graphite) to C(diamond) in kJ/mol is

Thermodynamics (Chapter Test - Medical) - Question 5

When 10 mL of a strong acid is added to 10 mL of an alkali, the temperature rises by 50C. If 100 mL of the
same acid is mixed with 100 mL of the same base, the temperature rise would be

Detailed Solution for Thermodynamics (Chapter Test - Medical) - Question 5
In answer it remaining same 5 degree centigrade it doesn't change because of heat of neutralization.. remain constant at constant pressure.
Thermodynamics (Chapter Test - Medical) - Question 6

Which of the following reactions defines  ?

Thermodynamics (Chapter Test - Medical) - Question 7

Calorific value of hydrogen gas is —143 kJ g—1. The standard enthalpy of formation of H2O will be

Thermodynamics (Chapter Test - Medical) - Question 8

The standard enthalpies of combustion of    C(graphite) and H2 (g) are respectively —3270 kJ
mol—1, —394 kJ mol—1 and —286 kJ mol—1. What is the
standard enthalpy of formation of  in  kJ mol—1 ?

Thermodynamics (Chapter Test - Medical) - Question 9

Match the column I with column II and mark the appropriate choice.

Thermodynamics (Chapter Test - Medical) - Question 10

At 25° C and 1 bar which one of the following has a non-zero ?

Thermodynamics (Chapter Test - Medical) - Question 11

The enthalpy of atomisation of CH4 and C2H6 are 360 and 620 kcal mol–1 respectively. The C – C bond energy is expected to be

Thermodynamics (Chapter Test - Medical) - Question 12

When 1 mole of oxalic acid is treated with excess of NaOH in dilute aqueous solution, 106 kJ of heat is
liberated. Predict the enthalpy of ionization of the acid

Thermodynamics (Chapter Test - Medical) - Question 13

The favourable condition for a process to be
spontaneous is

Thermodynamics (Chapter Test - Medical) - Question 14

The reaction    is spontaneous under standard conditions. Which of the following statements
must be true ?

I.  The reaction  is non-spontaneous under standard conditions.

II. A(g) will be completely converted to B(g) if sufficient time is allowed.

III. A(g) will be completely converted to B(g) rapidly

Thermodynamics (Chapter Test - Medical) - Question 15

ΔG0 for a reaction is 46.06 kcal/mole, Kp for the reaction at 300 K is

Detailed Solution for Thermodynamics (Chapter Test - Medical) - Question 15
ΔGdegree   = 46.06 kcal/mol = 46.06x1000x4.184J/mol
ΔGdegree = −RT ln KP = −2.303 RT log KP
⟹ 46.04x1000x4.184 = −2.303x8.31x300 log KP
⟹  log KP=−33.55
⟹ KP = 10^−33.55
Thermodynamics (Chapter Test - Medical) - Question 16

For the given reactions

It may be concluded that

Detailed Solution for Thermodynamics (Chapter Test - Medical) - Question 16
Because i guess, for hcl rxn, the gibbs free energy is positive that means it is a non spontaneous rxn , unlike for hf rxn, therefore hcl wont attack itself.
Thermodynamics (Chapter Test - Medical) - Question 17

If an endothermic reaction is non-spontaneous at freezing point of water and becomes feasible at its
boiling point, then

Thermodynamics (Chapter Test - Medical) - Question 18

Considering entropy (S) is a thermodynamic parameter, the criterion for the spontaneity of any process is

Thermodynamics (Chapter Test - Medical) - Question 19

If DfH0 (C, diamond) = 1.89 kJ mol–1, S0(C, diamond) = 2.38 J K–1 mol–1 and S0(C, graphite) = 5.74 J K–1
mol–1, then the transformation

C(diamond)→ C(graphite)

Thermodynamics (Chapter Test - Medical) - Question 20

Given :

which one of the following is true ?

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