Time And Distance - MCQ 1

# Time And Distance - MCQ 1

Test Description

## 20 Questions MCQ Test Quantitative Aptitude for Competitive Examinations | Time And Distance - MCQ 1

Time And Distance - MCQ 1 for Quant 2022 is part of Quantitative Aptitude for Competitive Examinations preparation. The Time And Distance - MCQ 1 questions and answers have been prepared according to the Quant exam syllabus.The Time And Distance - MCQ 1 MCQs are made for Quant 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Time And Distance - MCQ 1 below.
Solutions of Time And Distance - MCQ 1 questions in English are available as part of our Quantitative Aptitude for Competitive Examinations for Quant & Time And Distance - MCQ 1 solutions in Hindi for Quantitative Aptitude for Competitive Examinations course. Download more important topics, notes, lectures and mock test series for Quant Exam by signing up for free. Attempt Time And Distance - MCQ 1 | 20 questions in 40 minutes | Mock test for Quant preparation | Free important questions MCQ to study Quantitative Aptitude for Competitive Examinations for Quant Exam | Download free PDF with solutions
 1 Crore+ students have signed up on EduRev. Have you?
Time And Distance - MCQ 1 - Question 1

### A car started from Indore to Bhopal at a certain speed. The Car missed an accident at 40Kms away from Indore, then the driver decided to reduce Car speed to 4/5 of the original speed. Due to this, he reached Bhopal by a late of 1hr 15min.Suppose if he missed an accident at 80Km away from Indore and from then he maintained 4/5 of original speed then he would reach Bhopal by a late of 1hour. Then what is the original speed of the Car?

Detailed Solution for Time And Distance - MCQ 1 - Question 1

(x+40/s) + 5/4 = 40/s + 5x/4s — — — 1
(x+40/s) + 1 = 80/s + 5(x-40)/4s — — — 2
s = 40

Time And Distance - MCQ 1 - Question 2

### Two places A and B are at a certain distance. Ramu started from A towards B at a speed of 40 kmph. After 2 hours Raju started from B towards A at a speed of 60 kmph. If they meet at a place C then ratio of ratio of time taken by Raju to Ramu to reach Place C is 2:3. Then what is the distance between A and B?

Detailed Solution for Time And Distance - MCQ 1 - Question 2

40t 1 +60t 2 = d
T 1 /t 2 = 3/2
T 1 – t 2 = 2
Solving d = 480 Km

Time And Distance - MCQ 1 - Question 3

### Ramu started from A towards B at a speed of 20Km/hr and Raju started from B towards A. They crossed each other after one hour. Raju reached his destination 5/6 hour earlier than Ramu reached his destination.Then what is the distance between A and B?

Detailed Solution for Time And Distance - MCQ 1 - Question 3

1 = x/20 = D-x/s 2
5/6 = D(1/20 – 1/s 2)
D =50

Time And Distance - MCQ 1 - Question 4

Two Cars started at same time, same place and towards same direction. First Car goes at uniform speed of 12Km/hr. Second Car goes at speed of 4 Km/hr in first hour and increases it speed by 1 Km/hr for every hour. Then what is the distance traveled by car B when the both the Cars meet for the first time?

Detailed Solution for Time And Distance - MCQ 1 - Question 4

12*x = x/2(2*4+(x-1)*1)
X= 17
D = 17*12 =204

Time And Distance - MCQ 1 - Question 5

A man traveled 100 km by Bike in 2 hours. He then traveled in Bus for 8 hrs and then Train in 9 hrs. Ratio of Speeds of Bus to Train is 4:5. If speed of train is 4/5 of Bike speed then the entire journey covered by him in Km is?

Detailed Solution for Time And Distance - MCQ 1 - Question 5

Speed of train = 50
Bus = 32
Train = 40
Distance = 100+32*8+40*9 = 716

Time And Distance - MCQ 1 - Question 6

Car A leaves Delhi at a certain time, after 5 hours Car B leaves Delhi in the same direction as of A. Speed of Car A is 20Km/hr and Speed of Car B is 40Km/hr. In how much time Car B will be 20Km ahead of Car A?

Detailed Solution for Time And Distance - MCQ 1 - Question 6

20 =40*(t-5) – 20*t
T = 11
11-5 = 6

Time And Distance - MCQ 1 - Question 7

Two places A and B are at a distance of 480Km. Sita started from A towards B at the speed of 40Kmph. After 2 hours Gita started from B towards A at speed of 60 Kmph. They meet at a Place C then what is the difference between the time taken by them to reach their destinations from Place C?

Detailed Solution for Time And Distance - MCQ 1 - Question 7

t*40+ (t-2)*60 = 480
t=6
From Place C to A = C to B = 240
Then time taken by Sita = 6hours and GIta = 4 hours
Difference = 6-4 = 2 hours

Time And Distance - MCQ 1 - Question 8

Two Cars started at same time, same place and towards same direction. First Car goes at a speed of 5km/hr in first and 7 Km/hr in second hour and repeats the cycle over the entire journey. Similarly second Car goes at 4km/hr in first hour and 9km/hr in second hour and repeats the cycle over the entire journey.Then these two Cars for the first time for after how many hours of journey?

Detailed Solution for Time And Distance - MCQ 1 - Question 8

First car : 5,12,17
Second Car: 4,3,17

Time And Distance - MCQ 1 - Question 9

A police saw a Thief at a distance of 2km. When Police started chasing him Thief also started running. If the ratio of Speeds of Police to Thief is 5:4. Then thief was caught at a certain distance then how many Kms did police run to catch the Thief?

Detailed Solution for Time And Distance - MCQ 1 - Question 9

2+x/5 = x/4
X = 8
Police = 8+2 = 10

Time And Distance - MCQ 1 - Question 10

If a Car runs at 45Km/hr it reaches its destination by 10 min late. If it runs at 60Km/hr it is late by 4min. Then what is the correct time for the journey?

Detailed Solution for Time And Distance - MCQ 1 - Question 10

45(t+10) = 60(t+4)
T = 14

Time And Distance - MCQ 1 - Question 11

The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?

Detailed Solution for Time And Distance - MCQ 1 - Question 11

80/x – 80/(x+4) = 1
x(x+20) – 16(x+20) = 0
x = 16kmph
Increased speed = 20 kmph

Time And Distance - MCQ 1 - Question 12

Anita goes to College at 20 km/h and reaches college 4 minutes late. Next time she goes at 25 km/h and reaches the college 2 minutes earlier than the scheduled time. What is the distance of her school?

Detailed Solution for Time And Distance - MCQ 1 - Question 12

20*25/(25-20)*6/60=10.

Time And Distance - MCQ 1 - Question 13

Two places R and S are 800 km apart from each other. Two persons start from R towards S at an interval of 2 hours. Whereas A leaves R for S before B. The speeds of A and B are 40 kmph and 60 kmph respectively. B overtakes A at M, which is on the way from R to S. What is the ratio of time taken by A and B to meet at M?

Detailed Solution for Time And Distance - MCQ 1 - Question 13

Time taken by B to reach at M = 4h
Time taken by A to reach at M = 6h
Ratio = 6:4 = 3:2

Time And Distance - MCQ 1 - Question 14

Two places R and S are 800 km apart from each other. Two persons start from R towards S at an interval of 2 hours. Whereas A leaves R for S before B. The speeds of A and B are 40 kmph and 60 kmph respectively. B overtakes A at M, which is on the way from R to S. What is the extra time taken by A to reach at S?

Detailed Solution for Time And Distance - MCQ 1 - Question 14

Time taken by A to reach at Q = 800/40 = 20 hours
Time taken by B to reach at Q = 800/60 = 13 hours and 20 min
A takes 6hr 40 minutes extra time to reach at Q.

Time And Distance - MCQ 1 - Question 15

Ajay covers certain distance with his own speed but when he reduces his speed by 10kmph his time duration for the journey increases by 40 hours while if he increases his speed by 5 kmph from his original speed he takes 10 hours less than the original time taken. Find the distance covered by him.

Detailed Solution for Time And Distance - MCQ 1 - Question 15

x/(y – 10)  – x/y = 40
x = 4y(y-10) —(i)
x/y  – x/(y + 5) = 10
x = 2y(y + 5) — (ii) From (i) and (ii) ⇒ y = 25; x = 1500

Time And Distance - MCQ 1 - Question 16

The driver of an ambulance sees a college bus 40 m ahead of him after 20 seconds, the college bus is 60 meter behind. If the speed of the ambulance is 30 km/h, what is the speed of the college bus?

Detailed Solution for Time And Distance - MCQ 1 - Question 16

Relative Speed = (Total distance)/total time
= (60+40) /20 = 5 m/s = (5*18)/5 = 18 kmph
Relative Speed = (speed of ambulance – speed of College bus)
Speed of College bus = speed of ambulance – relative speed.
= 30-18 = 12 kmph.

Time And Distance - MCQ 1 - Question 17

Two places R and S are 800 km apart from each other. Two persons start from R towards S at an interval of 2 hours. Whereas A leaves R for S before B. The speeds of A and B are 40 kmph and 60 kmph respectively. B overtakes A at M, which is on the way from R to S. What is the distance from R, where B overtakes A?

Detailed Solution for Time And Distance - MCQ 1 - Question 17

Distance between R and M = 4 * 60 = 240

Time And Distance - MCQ 1 - Question 18

Two rabbits start running towards each other, one from A to B and another from B to A. They cross each other after one hour and the first rabbit reaches B, 5/6 hour before the second rabbit reaches A. If the distance between A and B is 50 km. what is the speed of the slower rabbit?

Detailed Solution for Time And Distance - MCQ 1 - Question 18

Let second rabbit takes x hr with speed s2
First rabbit takes x-5/6 hr with speed s1
Total distance = 50km
S1 = 50/(x-(5/6))
S2 = 50/x
As they cross each other in 1hr…
Total speed = s1 + s2
Now, T = D / S
50/(s1+s2) = 1
x = 5/2, 1/3
Put x = 5/2 in s2 –> 20km/hr

Time And Distance - MCQ 1 - Question 19

Pranav walked at 5 kmph for certain part of the journey and then he took an auto for the remaining part of the journey travelling at 25 kmph. If he took 10 hours for the entire journey, what part of journey did he travelled by auto if the average speed of the entire journey be 17 kmph

Detailed Solution for Time And Distance - MCQ 1 - Question 19

Total distance = 17*10 = 170

Let Journey travelled by auto in x hr

25 * x + (10-x ) 5 = 170

25 x + 50 – 5x = 170

x = 6

Required Distance = 6 * 25 = 150 km

Time And Distance - MCQ 1 - Question 20

Aravind started for the station half a km from his home walking at 1 km/h to catch the train in time. After 3 minutes he realised that he had forgotten a document at home and returned with increased, but constant speed to get it succeded in catching the train. Find his latter speed in kmph?

Detailed Solution for Time And Distance - MCQ 1 - Question 20

Distance covered in 3 minutes = 3*(1000/60) = 50

Now he has to cover (500+50)m in (30-3) minutes

Required speed = (550/1000)/(27/60) = 11/9 km/h

## Quantitative Aptitude for Competitive Examinations

33 videos|34 docs|140 tests
 Use Code STAYHOME200 and get INR 200 additional OFF Use Coupon Code
Information about Time And Distance - MCQ 1 Page
In this test you can find the Exam questions for Time And Distance - MCQ 1 solved & explained in the simplest way possible. Besides giving Questions and answers for Time And Distance - MCQ 1, EduRev gives you an ample number of Online tests for practice

## Quantitative Aptitude for Competitive Examinations

33 videos|34 docs|140 tests