UGC NET Paper 2 Computer Science Mock Test - 5 - UGC NET MCQ

• The process of dividing an analog signal into a string of discrete outputs, each of constant amplitude, is called Quantization.
• The process of enhancing an analog signal is called Amplification.
• Irregular behaviour or jerk or loss of continuity in analog signal is called Strobing.
• Conditioning is a process of manipulating an analog signal in a way that prepares it for the next stage of processing.

So, option (D) is correct.

Answer should be D.

The word polymorphism means having many forms. Typically, polymorphism occurs when there is a hierarchy of classes and they are related by inheritance. C⁺⁺ polymorphism means that a call to a member function will cause a different function to be executed depending on the type of object that invokes the function.

in C++ polymorphism indicates the form of member function that can be changed at run time such member functions are called virtual functions and the corresponding class is called polymorphic class. the objects of the polymorphic class , addressed by pointers change at run time and responds differently for the same message 

Data Scrubling ( Data Cleaning.):-The process of removing data in a database that is incorrect, incomplete, improperly formatted, or duplicated before sending it into data warehouse.

Subnormal fuzzy set: A fuzzy set wherein no membership function has its value equal to 1.

Convex fuzzy set: It is a fuzzy set which has a membership function whose membership values are strictly monotonically increasing or strictly monotonically decreasing or strictly monotonically increasing than strictly monotonically decreasing with increasing values for elements in the universe

Nonconvex fuzzy set: The membership values of the membership function are nor strictly monotonically increasing or decreasing or strictly monotonically increasing than decreasing.

The correct answer is option 2.

Key Points

FORMULA

Average weighting factor= (External Inputs(EI)×4)+( External Output(EO)×5)+( External Inquiries(EQ) ×4)+(External logical files(ILF)*10)+(External Interface File (EIF)*7)

CALCULATION:

Average weighting factor =(15 × 4 + 50 × 5 + 24 × 4 + 12 × 10 + 8 × 7)

=582

And productivity month is 70%

=582 × 0.7

=407.4
∴ Hence the correct answer is 408.74.

To insert a key into a hash table using open addressing with linear probing, we follow these steps:

1. Calculate the hash value of the key using the hash function.
2. If the calculated index is empty, insert the key at that index.
3. If the calculated index is occupied, probe linearly until an empty slot is found and insert the key at that slot.

Using the given hash function h(k) = k mod 9, we can calculate the hash value of each key as follows:

• h(22) = 22 mod 9 = 4
• h(28) = 28 mod 9 = 1
• h(23) = 23 mod 9 = 5
• h(12) = 12 mod 9 = 3
• h(13) = 13 mod 9 = 4

Steps -

• To insert the keys into the hash table using linear probing, we start by inserting key 22 at index 4.
• The next key, 28, is inserted at index 1 since index 4 is already occupied.
• The third key, 23, is inserted at index 5 since index 1 is occupied and index 4 is already occupied by key 22.
• The fourth key, 12, is inserted at index 3 since index 5 is occupied, index 1 is occupied by key 28, and index 4 is already occupied by key 22.
• Finally, when we try to insert the key 13, we calculate its hash value as h(13) = 4, which is the same as the hash value of key 22.
• Since index 4 is already occupied by key 22, we need to probe linearly to find the next available slot.
• We start at index 5 (next index after 4) and find that it is occupied by key 23.
• We continue probing linearly and find that the next available slot is index 6. Therefore, the key 13 is inserted at index 6.
• So the key 13 is inserted at index 6 in the hash table.

The correct answer is option 2.

Concept:

IEEE single-precision floating-point:

IEEE single-precision floating-point computer numbering format is a binary computing format that takes up 4 bytes (32 bits) of memory. Binary32 is the official name for the 32-bit base 2 formats in IEEE 754-2008. IEEE 754-1985 referred to it as single.

IEEE single-precision format:

Explanation:

The given data,

Decimal value =(-1)^s x 1.M x 2^{Base Exponent -Bias}

Bias value in IEEE single-precision format is 127

R_A = 1100 0001 0100 0000 0000 0000 0000 0000

RA sign= 1

RA Base Exponent =100 0001 0 = 130

R_A Mantisa = 100 0000 0000 0000 0000 0000 = 1.100 0000 0000.....

Decimal value = (-1)¹ x1.1 x2^130-127 =-1.1x2³= -1100 = (-12)₁₀

A=-12

RB = 0100 0010 0001 0000 0000 0000 0000 0000

RA sign= 0

RA Base Exponent =100 0010 0= 132

RA Mantisa = 001 0000 0000 0000 0000 0000 = 1.001 000000.....

Decimal value = (-1)0 x1.001 x2132-127 =+1.001x25= + 100100 = (+36)10

B=+36

RC = 0100 0001 0100 0000 0000 0000 0000 0000

RA sign= 0

RA Base Exponent =100 0001 0= 130

RA Mantisa =100 0000 0000 0000 0000 0000= 1.100 0000.....

Decimal value = (-1)0 x1.1 x2130-127 =+1.1x23= + 1100 = (+12)10

C=+12

Option 1: A + C = 0

True, A+C= -12+12=0

Hence it is true.

Option 2: C = A + B

False, A+B= -12+36=+24

it not equal to C. Hence it is false.

Option 3: B = 3C

True, B=3C

=3x+12 =36 =B

it equal to B. Hence it is true.

Option 4: (B - C) > 0

True, (B-C) >0

=(36-12)=24>0

Hence it is true.

Hence the correct answer is C = A + B.

Fuzzy logic machines are used in washing machines at assesses the various parameters of washing load and continuously adjusts the settings of spinning. Various system assesses and adjust some of parameters like:

i) The weight of the load

ii) Type of the fabric

iii) The amount and temperature of the water

iv) The amount of detergent

v) The dirt in the water or rinse needs

The Constructive Cost Model (COCOMO) is a procedural software cost estimation model developed by Barry W. Boehm.

The basic COCOMO model gives an approximate estimate of the project parameters. The basic COCOMO estimation model is given by the following expressions:

Effort = a1 х (KLOC) ^a2 PM

Tdev = b1 x (Effort)^b2 Months

Where

• KLOC is the estimated size of the software product expressed in Kilo Lines of Code,
• a1, a2, b1, b2 are constants for each category of software products,
• Tdev is the estimated time to develop the software, expressed in months,
• An effort is a total effort required to develop the software product, expressed in person months (PMs)

ATM

It is a data-link layer protocol like Ethernet, aimed at wide area networks (WANs) as well as local area networks (LANs). Whereas Ethernet is really geared towards carrying only Internet Protocol (IP) traffic, ATM is designed to integrate both data and voice needs in one network. It is efficient for call relay and it transmits all information including multiple service types such as data, video or voice which is conveyed in small fixed size packets called cells. Cells are transmitted asynchronously and the network is connection oriented.

SMDS (Switched Multimegabit Data Service)

It is a public, packet-switched service aimed at enterprises that need to exchange large amounts of data with other enterprises over the wide-area network SMDS extends the performance and efficiencies of a company's local area network (LANs) over a wide area on a switched,

X.25

It is Packet Switched networks allow remote devices to communicate with each other over private digital links without the expense of individual leased lines. Packet Switching is a technique whereby the network routes individual packets of HDLC data between different destinations based on addressing within each packet. An X.25 network consists of a network of interconnected nodes to which user equipment can connect. The user end of the network is known as Data Terminal Equipment (DTE) and the carrier’s equipment is Data Circuit-terminating Equipment (DCE)

Frame Relay

It is a simplified form of Packet Switching, similar in principle to X.25, in which synchronous frames of data are routed to different destinations depending on header information. The biggest difference between Frame Relay and X.25 is that X.25 guarantees data integrity and network managed flow control at the cost of some network delays.

White-box testing, sometimes called glass-box testing, is a test case design method that uses the control structure of the procedural design to derive test cases.

Using white-box testing methods, the software engineer can derive test cases that

(1) guarantee that all independent paths within a module have been exercised at least once

(2) exercise all logical decisions on their true and false sides

(3) execute all loops at their boundaries and within their operational bounds

The correct answer is Fields that can contain non-numeric data are to be removed and placed within their own tables with an associated Primary key.

Key Points

• Normalization rules and normal forms in the relational model do not discriminate between data types (numeric vs. non-numeric) in their requirements. Instead, normalization focuses on the structural aspects of the database to ensure redundancy is minimized and data integrity is maximized through the organization of fields, primary keys, and relationships between tables.

Option 1: ​In 1-bit images, each pixel is stored as a single byte.

False, 1-Bit, or 1bit means that each pixel is stored as a single bit. i.e. 0 or 1. The names black-and-white, B&W, monochrome or monochromatic are often used for this concept, but may also designate any images that have only one sample per pixel, such as grayscale images.

Option 2: A 1-bit image with a resolution of 640 × 480 needs a storage space of 640+480 bits.

False, 1-bit image is also known as 1-bit monochrome image because it contains one color that is black for off state and white for on state.

A 1-bit image with resolution 640 × 480 needs a storage space of 640 × 480 bits. 640 × 480 bits.

= (640 × 480) / 8 bytes

= (640 × 480) / (8 × 1024) KB

= 37.5KB.

Hence the correct answer is (i) False, (ii) False.

Data:

number of bits = n = 8

Formula:

Range of 2's compliment number with n bits is (–2^n-1 ) to +(2^n-1 – 1)

Smallest integer = –2n-1

largest integer = 2n-1 – 1

Calculation:

Smallest integer = –28-1 = –128

From the last question Schedule B is Pre-emptive priority schedule, so its Gantt chart is:

P1 wait for: 4-8 => 4

P2 wait for: 1-14 => 13

P3 wait for: 2-15 => 13

P4 wait for: 4-4 => 0

Average wait time = 30/4 = 7.5

It is clear that it is FCFS because the order of execution is the order of arrival.

Correct answer is 14

Pre-emptive priority schedule, so its Gantt chart is:

TAT = CT - AT (Completion Time (CT), Arrival Time (AT))

TAT = 15 - 1 = 14

The correct answer is StuAadhar

Key PointsAn alternate key in database terminology is a candidate key that is not chosen as the primary key but is still unique and can identify each record in a table. For the Student table, the ideal alternate key would be an attribute that uniquely identifies each student, aside from the primary key (which we may assume to be something like StuID if following common conventions).

• StuName is generally not unique because different students can share the same name.
• StuContact could be unique, as typically each student would have a unique contact number. However, this depends on the policy of the organization (e.g., whether parents' contact numbers are used for younger students).
• StuAadhar is a highly likely candidate for uniqueness. The Aadhar number is a unique identifier issued by the UIDAI to residents of India, and it is meant to be a unique identifier for each individual.
• StuClass would not be unique as many students belong to the same class.

Given these options, the most definitive and universally unique across all possible scenarios would be: StuAadhar
This assumes that StuAadhar refers to the Aadhar number, which is unique to every individual in India. As such, it would serve as an excellent alternate key, assuming that uniqueness and the ability to identify each record in the table are the primary criteria.

The correct answer is Select BookID from Stulibrary where Return_date is NULL;

Key PointsThis query fetches the BookID of books from the Stulibrary table where the Return_date is NULL, indicating that the books have been issued but have not yet been returned.

• SELECT BookID: This retrieves only the `BookID` column, focusing on book identification.
• FROM Stulibrary: This specifies the `Stulibrary` table as the source of data.
• WHERE Return_date is NULL: This crucial part filters the results. A `NULL` value in the `Return_date` column indicates that the book has not been returned yet.

The correct answer is option 3.

Concept:

Pre-increment (++i) :

Before assigning the value to the variable, the value is incremented by one.

Post-increment (i++) :

After assigning the value to the variable, the value is incremented by one.

Explanation:

The given data,

p=2

q=3

p = q++;

Here post-increment for variable q. After assigning the value to the variable, the value is incremented by one. i.e(p has 3 and q has 4)

p=3

Now q=4

Hence the correct answer is to assign a value of 3 to p.

Correct answer: Option 2

Explanation:

• A software process model is a blueprint of the flow of processes that should be followed when developing a software. This model defines each task, the input and output of each task and the sequence in which the tasks should be carried out.
• The linear sequential model, prototype model and spiral model are examples of a software process model. Each model has a different approach to the flow of processes for developing a software.
• The COCOMO model, on the other hand, is a cost estimation model. It identifies the amount of labour required and the schedule to be followed.

Important Points:

• The COCOMO model, short for COnstructive COst MOdel, is used to determine the monetary cost of a software project. The cost is directly related to the manpower required (effort) and how quickly it is required (schedule).
• Either the schedule influences the effort or the effort influences the schedule. The project manager decides which of the two factors are more important and lets it be the deciding factor.

The automaton which allows transformation to a new state without consuming any input symbols is NFA-l. NFA-l or e-NFA is an extension of Non-deterministic Finite Automata which are usually called NFA with epsilon moves or lambda transitions. 

Nondeterministic finite automaton with ε-moves (NFA-ε) is a further generalization to NFA. This automaton replaces the transition function with the one that allows the empty string ε as a possible input. The transitions without consuming an input symbol are called ε-transitions.

A Lexeme is a sequence of alphanumeric characters in a token. The term is used in both the study of language and in the lexical analysis of computer program compilation. In the context of computer programming, lexemes are part of the input stream from which tokens are identified.

The parity bit ensures that the total number of 1-bits in the string is even or odd. Accordingly, there are two variants of parity bits: even parity bit and odd parity bit. If that count is odd, the parity bit value is set to 1, making the total count of occurrences of 1s in the whole set (including the parity bit) an even number. In the case of odd parity, the coding is reversed. For a given set of bits, if the count of bits with a value of 1 is even, the parity bit value is set to 1 making the total count of 1s in the whole set (including the parity bit) an odd number. If the count of bits with a value of 1 is odd, the count is already odd so the parity bit's value is 0.