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JEE Exam  >  JEE Tests  >  VITEEE: Subject Wise and Full Length MOCK Tests  >  VITEEE PCME Mock Test - 12 - JEE MCQ

VITEEE PCME Mock Test - 12 - JEE MCQ


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30 Questions MCQ Test VITEEE: Subject Wise and Full Length MOCK Tests - VITEEE PCME Mock Test - 12

VITEEE PCME Mock Test - 12 for JEE 2024 is part of VITEEE: Subject Wise and Full Length MOCK Tests preparation. The VITEEE PCME Mock Test - 12 questions and answers have been prepared according to the JEE exam syllabus.The VITEEE PCME Mock Test - 12 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for VITEEE PCME Mock Test - 12 below.
Solutions of VITEEE PCME Mock Test - 12 questions in English are available as part of our VITEEE: Subject Wise and Full Length MOCK Tests for JEE & VITEEE PCME Mock Test - 12 solutions in Hindi for VITEEE: Subject Wise and Full Length MOCK Tests course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt VITEEE PCME Mock Test - 12 | 125 questions in 150 minutes | Mock test for JEE preparation | Free important questions MCQ to study VITEEE: Subject Wise and Full Length MOCK Tests for JEE Exam | Download free PDF with solutions
VITEEE PCME Mock Test - 12 - Question 1
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If x = a (θ + sinθ), y = a(1 - cosθ), then at θ = π/2, the length of the normal is

VITEEE PCME Mock Test - 12 - Question 2
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Area bounded by parabola y2 = x and st.line 2 y = x is

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VITEEE PCME Mock Test - 12 - Question 3
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VITEEE PCME Mock Test - 12 - Question 4
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If w3 = 1 and w ≠ 1, then (1 + w)(1 + w2)(1 + w4)(1 + w8) =
VITEEE PCME Mock Test - 12 - Question 5
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If R → R is continuous such that f (x + y)   = f(x) + f(y), ∀ x ∈ R , y ∈ R , and f(1) = 2 then f(100) =
VITEEE PCME Mock Test - 12 - Question 6
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If α and β are real them 

VITEEE PCME Mock Test - 12 - Question 7
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The area of the curve |x|+|y|=4 is
VITEEE PCME Mock Test - 12 - Question 8
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If the function f is defined by f(x)   = x/1 + | x | then at what points is f differentiable
VITEEE PCME Mock Test - 12 - Question 9
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Which of the following is a solution of the differential equation ( dy/dx )2 - x dy/dx + y = 0
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 9

( d/ dx )2 - x . dy/dx + y = 0
y = 2x - 4
∴ dy dx = 2
So, ( dy dx )2 - x . dy dx + y
= (2)2 - x x 2 + 2x - y
= 4 - 2x + 2x - y
= 0

VITEEE PCME Mock Test - 12 - Question 10
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The solution of the differential equation cos(x + y)dy = dx is
VITEEE PCME Mock Test - 12 - Question 11
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Detailed Solution for VITEEE PCME Mock Test - 12 - Question 11

VITEEE PCME Mock Test - 12 - Question 12
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(d2y/dx2)2 + x(dy/dx)2 is a differential equation of
VITEEE PCME Mock Test - 12 - Question 13
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4[cot-13 + cosec-1(√5)] is equal to
VITEEE PCME Mock Test - 12 - Question 14
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The solution of differential equation 2y sin x(dy/dx)=2 sinx cosx - y2 cosx; x=(π/2), y=1, is
VITEEE PCME Mock Test - 12 - Question 15
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The function f(x) = x3 - 3x2 - 24x + 5 is increasing in the interval
VITEEE PCME Mock Test - 12 - Question 16
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The value of  is equal to
VITEEE PCME Mock Test - 12 - Question 17
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VITEEE PCME Mock Test - 12 - Question 18
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If a , b , c are positive then
VITEEE PCME Mock Test - 12 - Question 19
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 then a =
VITEEE PCME Mock Test - 12 - Question 20
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Detailed Solution for VITEEE PCME Mock Test - 12 - Question 20

VITEEE PCME Mock Test - 12 - Question 21
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Directions: In this type of questions, some particular words are assigned certain substituted names. Then a question is asked that is to be answered in the substituted code language.

If 'sand' is called 'air', 'air' is called 'plateau', 'plateau' ia called 'well', 'well' is called 'island' and 'island' is called 'sky', then from where will a woman draw water?
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 21

A woman shall draw water from a 'well' but a 'well' is called 'island' . So, the woman will draw water from an 'island'.

Hence, option B is correct.

VITEEE PCME Mock Test - 12 - Question 22
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Directions: In this type of questions, some particular words are assigned certain substituted names. Then a question is asked that is to be answered in the substituted code language.

If 'cushion' is called 'pillow', 'pillow' is called 'mat', 'mat' is called 'bedsheet' and 'bedsheet' is called 'cover', which will be spread on the floor ?
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 22

'mat' will be spread on the floor But 'mat' is called 'bedsheet'.So, a 'bedsheet' will be spread on the floor.

Hence, option B is correct.

VITEEE PCME Mock Test - 12 - Question 23
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Directions: In this type of questions, some particular words are assigned certain substituted names. Then a question is asked that is to be answered in the substituted code language.

If 'rain' is 'water', 'water' is 'road', 'road' is 'cloud', 'cloud' is 'sky', 'sky' is 'sea' and 'sea' is 'path', where do aero planes fly ?
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 23

The aero planes fly in the "sky" and the 'sky' is called 'sea'.So, the aero planes fly the 'sea'.

Hence, option B is correct.

VITEEE PCME Mock Test - 12 - Question 24
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Directions: Study the following graph carefully to answer the questions that follow.
Number of Students (In thousands) in Two Different Universities in Six Different Years

Q. What is the sum of the number of students in university 1 in the year 2007 and the number of students in university 2 in the year 2011 together?
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 24

Number of students in university 1 in 2007 = 10000 
Number of students in university 2 in 2011 = 30000
∴  Required sum = 10000 + 30000 = 40000.

VITEEE PCME Mock Test - 12 - Question 25
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Directions: In the question below, the sales of TV and laptop in the subsequent years from 2004 to 2009 is given. The figures given to you is in million. Based on the figure answer the questions below.

Q. How many times do the sales of a laptop less than the TV in the given years?
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 25

Here the sales of televisions and laptops of six different years are given. You need to see that in which year the sale of TV was greater than the sale of the laptop. The values of different sales of units are given to you in the radar diagram above.
From the figure you can see that sales of the laptops in 2004 were lower than the sales TVs in 2004, similarly, sales of a laptop in 2005, 2008, and 2009 was lower than the sale of TVs in that year. So, there are four years where the sale of the laptop was lower than the sale of TV. Thus, the correct answer is D.

VITEEE PCME Mock Test - 12 - Question 26
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Directions: In the question below, the sales of TV and laptop in the subsequent years from 2004 to 2009 is given. The figures given to you is in million. Based on the figure answer the questions below.

Q. Which item and for which year shows the highest percentage increase in the sales in the previous year?
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 26

In this question, we need to find the increase in the percentage of the given items in comparison to previous years. Instead of checking all the years, we will only check percentage increase for the one given in the option. For laptop 2007, in the previous year, the sales were 30 million while in 2006 it was 25.5 so there is an increase of 4.5 million units. Therefore percentage increase will be 4.5/25.5 x 100 = 18%.
Similarly for TV 2007 it will be, 2.5/22.5 x 100 = 11.11 %. For Laptop 2006 it will be, 7.5/15 x 100 = 50 % and for TV 2009, it will be 5/25 x 100 = 20 %. So for laptop 2006, the percentage increase in sales is the highest. Thus, the correct answer is C.

VITEEE PCME Mock Test - 12 - Question 27
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Directions: In the question below, the sales of TV and laptop in the subsequent years from 2004 to 2009 is given. The figures given to you is in million. Based on the figure answer the questions below.

Q. Find the ratio of the total number of televisions sold to the total number of laptops sold in all these years.
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 27

Here, you only have to add the total number of televisions laptop sold in all these years and compare them to find the ratio. The total number of televisions sold from 2004 to 2009 are 25 + 22.5 + 22.5 + 25 + 25 + 30 = 150. And the total number of laptops sold are: 20 + 15 + 25 .5 + 30 + 20 + 10 = 120.5. Thus the ratio of the is 150: 120.5 = 5: 4. So, the correct answer is C.

VITEEE PCME Mock Test - 12 - Question 28
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Directions: Study the following graph carefully and answer the question given below.

Q. What is the difference between the total number of hard disks and mouses produced by Company 'X' in the year 2010 and the total number of keyboards and pen drives produced by Company 'X' in the year 2015?
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 28

Total number of hard disks and mouses produced by Company 'X' in the year 2010 = 6 + 30 = 36 thousand = 36,000
Number of keyboards and pen drives produced by Company 'X' in the year 2015 = 55 + 36 = 91 thousand = 91,000
Required difference = 91,000 - 36,000 = 55,000

VITEEE PCME Mock Test - 12 - Question 29
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Directions: Study the following graph carefully and answer the question given below.

Q. What was the respective ratio between the number of pen drives produced by Company 'X' in the years 2010, 2011, 2014 and 2015 and the number of hard disks produced by Company 'X' in the years 2011, 2012, 2015 and 2017?
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 29

The number of pen drives produced by Company 'X' in years 2010, 2011, 2014 and 2015 = 10 + 15 + 22 + 36 = 83 (in thousands)
The number of hard disks produced by Company 'X' in years 2011, 2012, 2015 and 2017 = 10 + 18 + 28 + 35 = 91 (in thousands)
Required ratio = 83 : 91

VITEEE PCME Mock Test - 12 - Question 30
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A and B together can do a piece of work in 50 days. If A is 40% less efficient than B, in how many days can A working alone complete 60% of the work?
Detailed Solution for VITEEE PCME Mock Test - 12 - Question 30

Given:

A and B together can do a piece of work in 50 days.

A is 40% less efficient than B

Concept used:

Total work = Efficiency of the workers × time taken by them

Calculation:

Let the efficiency of B be 5a

So, efficiency of A = 5a × 60%

⇒ 3a

So, total efficiency of them = 8a

Total work = 8a × 50

⇒ 400a

Now,

60% of the work = 400a × 60%

⇒ 240a

Now,

Required time = 240a/3a

⇒ 80 days

∴ A can complete 60% of the work working alone in 80 days.

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