ZS Associates Aptitude Questions and Answers - Interview Preparation MCQ

Distance covered in 72 sec = (300+900)m
Speed = (1200/72)m/sec
=(50/3) m/sec
= (50/3 × 18/5) km/hr = 60 km/hr

2X + Y = 7000
 X + 2Y = 9800
 Solving (i) and (ii), we get Y = 4200

To reach the winning point , A will have to cover a distance of 500 – 140= 360 metre ratio of the speeds of two contestants A and B is 3 : 4
i.e., when A covers 3 metre, B covers 4 metre.
=> When A covers 360 metre, B covers 43×360 = 480 metre.
Remaining distance B have to cover = 500-480= 20 metre
=> A wins by 20 metre

Let the number of 25 p, 10 p and 5 p coins be x, 2x and 3x respectively.
Then, sum of their values = [25x/100 + (10 * 2x)/100 + (5 * 3x)/100] = Rs.
60x/100
60x/100 = 30 => x = 50.
Hence, the number of 5 p coins = 3 * 50 = 150.

Let the loan taken be Rs. X , then
X × 6/100 × 1 + X × 6.5/100 × 1 + X × 7/100 × 1 + X × 7.5/100 × 1 = 3375
=> (6+ 6.5 +7 +7.5) × X/100 = 3375
=> X = (3375 × 100/27) = 12500

Let w be the time taken in one way by walking and C be the time taken in one way By car.

(A + B)’s 1 day work = 1/12;
(B + C)’s 1 day work = 1/15;
(A + C)’s 1 day work = 1/20
Adding, we get: 2(A + B + C)’s 1 day work = (1/12 + 1/15 + 1/20) = 1/5
(A + B + C)’s 1 day work = 1/10
So, A, B and C together can complete the work in 10 days.

=Volume of the wooden boxVolume of one rectangular box=800×700×600/8×7×6=1000000. 

The word ‘LEADING’ has 7 different letters.
When the vowels EAI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters LNDG (EAI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 3! = 6 ways.
 Required number of ways = (120 x 6) = 720

Therefore, correct option is C.

Clearly, the numbers are (23 x 13) and (23 x 14).
 Larger number = (23 x 14) = 322.

 Required number = (23 – 21)= 2.