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Probability- Assertion & Reason Type Questions - Free with Solutions


MCQ Practice Test & Solutions: Test: Probability- Assertion & Reason Type Questions (10 Questions)

You can prepare effectively for Class 9 Class 9: Additional Practice with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Probability- Assertion & Reason Type Questions". These 10 questions have been designed by the experts with the latest curriculum of Class 9 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

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Test: Probability- Assertion & Reason Type Questions - Question 1

Direction: In the following questions, a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements, mark the correct

answer as

Assertion : Two well balanced dice are rolled and the numbers that turn up are observed. Then the number of elements in sample space is 12.

Reason : When two dice are rolled, number of elements in sample space is 6 x 6.

Detailed Solution: Question 1

When two dice are thrown simultaneously, thus number of event can be 62 = 36 because each die has 1 to 6 number on its faces. Then the possible outcomes are shown in the below table.

Test: Probability- Assertion & Reason Type Questions - Question 2

Direction: In the following questions, a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements, mark the correct

answer as

Assertion : Two coins are tossed. Number of elements in the sample space is 4.

Reason : When a coin is tossed n times then the number of elements in its sample space is 2n.

Detailed Solution: Question 2

Sample space S = {(H, H), (H, T),(T, H),(T, T)}

Number of sample space n(S) = 4

D = getting no head

D = {(T, T)}

n(D) = 1

Test: Probability- Assertion & Reason Type Questions - Question 3

Direction: In the following questions, a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements, mark the correct

answer as

Assertion : A fair die is rolled. Then the probability of getting an even number is 1/2 and probability of getting an odd number is 1/2.

Reason : Possible outcomes when a fair die is rolled is (1, 2, 3, 4, 5, 6).

Detailed Solution: Question 3

Possible outcomes when a die is thrown = {1, 2, 3, 4, 5, 6}

P (getting an odd number) = 3/6 = 1/2

P (getting an even number) = 3/6 = 1/2

Test: Probability- Assertion & Reason Type Questions - Question 4

Direction: In the following questions, a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements, mark the correct

answer as

Assertion : If E1, E2 , .........., En are n elementary events associated to a random experiment, then P(E1) + P(E2) PE +.....+ P(En) = 1

Reason : For any event ‘A’ associated to an experiment, we have -1 ≤ P(A) ≤ 1

Detailed Solution: Question 4

Given = p(E1) + p(E2) = X

p(E3) = 1/3

In an elementary event the sum of all the events is equal to 1

p(E1) + p(E2) + p(E3) = 1

X + 1/3 = 1

X = 1 - 1/3

X = 2/3

Test: Probability- Assertion & Reason Type Questions - Question 5

Direction: In the following questions, a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements, mark the correct

answer as

Assertion : In a class there are x boys. and y girls, A student is selected at random, then the probability of selecting a girl is y/x.

Reason : Probability of an event E of an experiment is ratio of the number of trials in which event E has happened to the total number of trials.

Detailed Solution: Question 5

P (selecting a girl) = y/(x+y)

Test: Probability- Assertion & Reason Type Questions - Question 6

Direction: In the following questions, a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements, mark the correct

answer as

Assertion : A die is thrown. Let E be the event that number appears on the upper face is less than 1, then P(E) = 1/6

Reason : Probability of impossible event is 0.

Detailed Solution: Question 6

When a die is thrown, then number of outcomes are 1, 2, 3, 4, 5, 6

P(number appear on the upper face is less than 1) = 0

Test: Probability- Assertion & Reason Type Questions - Question 7

Direction: In the following questions, a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements, mark the correct

answer as

Assertion : Tossing a coin 50 times is called an event.

Reason : The possible outcomes of an experiment are called events.

Detailed Solution: Question 7

Tossing a coin 50 times is called an experiment.

Test: Probability- Assertion & Reason Type Questions - Question 8

Direction: In the following questions, a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements, mark the correct

answer as

Assertion : A coin is tossed two times. Probability of getting at least two heads is 1/4.

Reason : When a coin is tossed two times, then the sample space is {HH, HT, TH, TT}

Detailed Solution: Question 8

Number of total outcomes when a coin is tossed 2 times i.e., {HH, HT, TH, TT} = 4

P(getting at least two heads) = 1/4

Test: Probability- Assertion & Reason Type Questions - Question 9

A die is rolled if the number on a die is even then a coin is tossed once and if the number on a die is odd, then a coin is tossed twice. Match the events in Column-I with their probabilities in Column-II

Detailed Solution: Question 9

(P)

n(S) = 18

Let E be the event that 2 heads appears then

n (E) = 3

(Q)

n (S) = 18

Let F be the event that at least 1 head appears

then n(F) = 12

(R)

n(S) = 18

Let G be the event that die shows an even number

and coin shows exactly two heads. Then n(G) = 0

(S)

n(S) = 18

Let H be the event that die shows an odd number and coin shows at least one tail.

n(H) = 9

Test: Probability- Assertion & Reason Type Questions - Question 10

A NGO selected 2000 families at random and surveyed them to determine number of children in a family. The data is given below:

If one family is chosen at random then, match the Column-I with their corresponding probabilities in Column-II.

Detailed Solution: Question 10

(P) Let E be the event that chosen family has 1 boy and 2 girls

Hence, n(E) = 300

(Q) Let F be the event that chosen family has no boy

n(F) = 200

(R) Let G be the event that chosen family has 1 boy and 1 girl

Hence, n(G) = 400

(S) Let H be event that chosen family has 2 boys and 1 girl

Hence, n(H) = 600

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